1. Briefly explain why the Suzuki reaction can take place in aqueous solution whereas a Grignard reaction requires anhydrous conditions. 2. Under the required basic conditions, the Suzuki coupling is not efficient when the organic electrophile (RX) is an alkyl halide. What undesired side reaction is possible under basic conditions? 3. Compound A was prepared by sequential Suzuki cross-coupling reactions. First, compound 1 was treated with an aryl iodide to give compound 2, which was then treated with an aryl boronic acid to produce compound A. -OME OH HONOZ • Draw structures for the aryl iodide, boronic acid, and compound 2. 4. A common way to determine the catalyst:limiting reactant ratio in a catalytic reaction is to report the amount of catalyst used in mol%. For example, 5 mol% catalyst means that the reaction uses 5% as much catalyst as limiting reactant. Showing all your work, calculate the mol% of Pd used in this reaction where R and R' = H.
Answers
1. The Suzuki reaction can take place in aqueous solution because it involves the use of a boron-based compound (boronic acid) that is stable in the presence of water. On the other hand, the Grignard reaction requires anhydrous conditions because Grignard reagents (organomagnesium compounds) are highly reactive with water, leading to the formation of alkanes and magnesium salts, thus deactivating the reagent.
When the organic electrophile (RX) in the Suzuki coupling is an alkyl halide, an undesired side reaction called elimination can occur under basic conditions. This elimination process results in the formation of an alkene and a halide salt, decreasing the efficiency of the Suzuki coupling. As the specific compound A is not provided, I am unable to draw the structures for the aryl iodide, boronic acid, and compound 2. Please provide the structure of compound A for further assistance. To calculate the mol% of Pd used in the reaction, you'll need to know the moles of the limiting reactant and the moles of Pd catalyst used. If that information is not provided, I cannot give you a specific answer. However, here is the formula to calculate mol%: Mol% of Pd = (moles of Pd catalyst / moles of limiting reactant) * 100
Know more about aqueous solution here;
https://brainly.com/question/26856926
#SPJ11
1. The Suzuki reaction can take place in aqueous solution because the reaction conditions involve a palladium catalyst and a base, which can both be dissolved in water. Additionally, the reactants used in the Suzuki reaction, aryl halides and boronic acids, are both stable in water. In contrast, Grignard reagents are highly reactive with water, which can interfere with the reaction, so anhydrous conditions are necessary to prevent the Grignard reagent from reacting with water instead of the desired organic substrate.
2. When the organic electrophile (RX) is an alkyl halide, a side reaction called β-elimination can occur under basic conditions, resulting in the formation of an alkene instead of the desired cross-coupling product.
3. Aryl iodide: I-C6H4-OMe Boronic acid: B(OH)2-C6H4-NO2 Compound 2: H-C6H4-B(OH)2
4. To calculate the mol% of Pd used in this reaction where R and R' = H, we need to know the molar mass of Pd and the molar mass of the limiting reactant. Assuming the limiting reactant is the aryl halide, we can use its molar mass to calculate the amount of catalyst needed for 5 mol%: Molar mass of aryl halide (C6H5X) = 157.12 g/mol
5 mol% of catalyst = 0.05 mol Pd/mol aryl halide Molar mass of Pd = 106.42 g/mol.
To determine the amount of Pd needed for the reaction, we can multiply the mol% by the amount of aryl halide used: 0.05 mol Pd/mol aryl halide x 0.5 mol aryl halide = 0.025 mol Pd
Finally, we can convert the amount of Pd used to mol% by dividing it by the amount of limiting reactant used: 0.025 mol Pd / 0.5 mol aryl halide x 100% = 5 mol% Pd.
For more questions on: Suzuki
https://brainly.com/question/30426228
#SPJ11
Related Questions
Which element has the atomic number of 17?
Answers
Step 1. Show that for the Logistic Activation function for the neurons as below: φ(v)=
1+exp(−v)
1
Then the derivative is as following: φ
′
(t)=φ(t)(1−φ(t)) Step 2. Using the model of a single neuron, calculate the input of the neuron j, net j, as: ∑
i=1
p
(W
ji
X
i
+ Threshold ) where X
i
is the activation of previous layer neuron i W
ji
is the weight of going from node i to node j p is the number of neurons in the previous layer Step 3. Using the error function below, E(
x
)=
2
1
∑
k=1
K
(y
k
(
x
)−t
k
(
x
))
2
Take the partial derivative with respect to the weight as:
∂w
jk
∂E(
x
)
Use chain rule of calculus and simplify it using results of steps 1 and 2 , show that:
∂w
jk
∂E(
x
)
=−y
j
φ(net
j
)(1−φ(net
j
))(t
j
−y
j
)
Answers
Step 1: Deriving the derivative of the logistic activation function.
Step 2: Calculating the input of neuron j (net j).
Step 3: Deriving the expression ∂w_jk / ∂E(x).
Let's go through the steps and derive the expression you mentioned.
Step 1: Deriving the derivative of the logistic activation function
We start with the logistic activation function:
φ(v) = 1 / (1 + exp(-v))
To find its derivative, we differentiate φ(v) with respect to v:
φ'(v) = d/dv [1 / (1 + exp(-v))]
Using the quotient rule, we can differentiate the numerator and denominator separately:
φ'(v) = [0 - (1) * (exp(-v))] / (1 + exp(-v))²
Simplifying, we get:
φ'(v) = exp(-v) / (1 + exp(-v))²
Expanding the denominator:
φ'(v) = exp(-v) / (1 + 2exp(-v) + exp(-2v))
Simplifying further:
φ'(v) = 1 / (1 + exp(-v)) * (exp(-v) / (1 + exp(-v)))
Canceling out the common terms:
φ'(v) = 1 / (1 + exp(-v)) * (1 - 1 / (1 + exp(-v)))
Combining the fractions:
φ'(v) = φ(v) * (1 - φ(v))
Therefore, the derivative of the logistic activation function φ(v) is given by:
φ'(v) = φ(v) * (1 - φ(v))
Step 2: Calculating the input of neuron j (net j)
The input of neuron j (net j) can be calculated as:
net_j = ∑(i=1 to p) (W_ji * X_i + Threshold)
Where:
X_i is the activation of the previous layer neuron i.
W_ji is the weight going from node i to node j.
Threshold is the bias or threshold value.
Step 3: Deriving the expression ∂w_jk / ∂E(x)
To derive the expression, we'll use the chain rule and simplify it using the results from Steps 1 and 2.
Assuming E(x) is the error function, and we are taking the partial derivative with respect to the weight w_jk, the expression is:
∂w_jk / ∂E(x)
Using the chain rule, we have:
∂E(x) / ∂w_jk = ∂E(x) / ∂net_j * ∂net_j / ∂w_jk
Now, let's simplify each term:
∂E(x) / ∂net_j = -2 * (t_j - y_j) (where t_j is the target output and y_j is the actual output of neuron j)
∂net_j / ∂w_jk = X_k (where X_k is the activation of the previous layer neuron k)
Multiplying the two terms together:
∂E(x) / ∂w_jk = -2 * (t_j - y_j) * X_k
Now, we'll substitute φ(net_j) with y_j, using the result from Step 1:
φ(net_j) = y_j
Finally, using the derivative result from Step 1, we have:
∂E(x) / ∂w_jk = -2 * (t_j - y_j) * X_k * φ(net_j) * (1 - φ(net_j))
Substituting y_j with φ(net_j), we get the desired expression:
∂E(x) / ∂w_jk = -y_j * φ(net_j) * (1 - φ(net_j)) * (t_j - y_j)
Therefore, we have shown that:
∂w_jk / ∂E(x) = -y_j * φ(net_j) * (1 - φ(net_j)) * (t_j - y_j)
Learn more about logistic activation function from the link given below.
https://brainly.com/question/33140065
#SPJ4
What is a neutralization reaction?
O A. A reaction in which the product is either acidic or basic
O B. A reaction that involves neutral reactants
O c. A reaction in which the reactants are a salt and water
O D. A reaction that removes essentially all Ht and OH
Answers
Answer:
D or A your choice
Explanation:
uhhh didnt u- nvm
A neutralization reaction is when an acid and a base react to form water and a salt and involves the combination of H+ ions and OH- ions to generate wate
for the following endothermic reversible reaction at equilibrium, how will removing no(g) affect it? 4no(g) 6h2o(g) rightwards harpoon over leftwards harpoon with blank on top 4nh3(g) 5o2(g)
Answers
Removing NO(g) from the equilibrium of the endothermic reversible reaction will shift the equilibrium to the left, resulting in an increase in the production of NO(g) and H₂O(g) while consuming NH₃(g) and O₂(g).
For the endothermic reversible reaction at equilibrium, removing NO(g) will affect it as follows:
Reaction: 4NO(g) + 6H₂O(g) ⇌ 4NH₃(g) + 5O₂(g)
Since this is an endothermic reaction, it means that the reaction absorbs heat from its surroundings when it proceeds in the forward direction (left to right). At equilibrium, the rates of the forward and reverse reactions are equal.
When you remove NO(g) from the system, you are essentially decreasing the concentration of NO(g) in the reaction mixture. According to Le Chatelier's principle, the system will counteract this change by shifting the position of equilibrium to restore the balance.
In this case, the equilibrium will shift to the left to replenish the NO(g) that was removed. This means the reaction will proceed more in the reverse direction (right to left), producing more NO(g) and H₂O(g) while consuming NH₃(g) and O₂(g).
In summary, removing NO(g) from the endothermic reversible reaction at equilibrium will cause the reaction to shift to the left, producing more NO(g) and H₂O(g) while consuming NH₃(g) and O₂(g).
To know more about the endothermic reversible reaction refer here :
https://brainly.com/question/17163217#
#SPJ11
what quantity in moles of chlorine gas at 120.0 °c and 33.3 atm would occupy a vessel of 12.0 l?
Answers
The quantity in moles of chlorine gas at 120.0 °C and 33.3 atm that would occupy a vessel of 12.0 L is 0.754 moles.
We can use the Ideal Gas Law to solve for the quantity of moles of chlorine gas. The formula for the Ideal Gas Law is PV = nRT, where P is pressure, V is volume, n is the quantity in moles, R is the gas constant, and T is temperature in Kelvin.
First, we need to convert the temperature from Celsius to Kelvin: 120.0°C + 273.15 = 393.15 K.
Next, we can rearrange the Ideal Gas Law to solve for n:
n = PV/RT
We plug in the values given in the problem:
P = 33.3 atm
V = 12.0 L
R = 0.0821 L•atm/mol•K (gas constant)
T = 393.15 K
n = (33.3 atm x 12.0 L) / (0.0821 L•atm/mol•K x 393.15 K)
n = 0.754 moles
Therefore, the quantity in moles of chlorine gas at 120.0°C and 33.3 atm that would occupy a vessel of 12.0 L is 0.754 moles.
To Know more about moles, visit
https://brainly.com/question/29367909
#SPJ11
dieckmann neither a nor b can adopt s-trans conformation both can adopt s-cis conformation both are in s-trans conformation both are in s-cis conformation neither a nor b can adopt s-cis conformation only b can adopt s-cis conformation only a can adopt s-cis conformation
Answers
It is not possible to determine the correct statement from the given options without additional information or context.
The statement provided consists of several statements regarding the conformation of compounds A and B. However, without knowing the specific structures of compounds A and B or any additional information about their molecular characteristics, it is impossible to determine which statement is correct.
Conformation refers to the spatial arrangement of atoms in a molecule, and it is influenced by factors such as bond angles, steric hindrance, and electronic interactions. To accurately determine the conformation of compounds A and B, a detailed analysis of their structures and molecular properties would be necessary.
To know more about Molecular characteristics :
brainly.com/question/14738862
#SPJ11
In the ground state an atom of which element has seven valence electrons.
Answers
Answer: Fluorine (see explanation)
Explanation:
Stream “Do We Have a Problem” by Nicki Minaj and Lil Baby coming out 2/4/22
T = 409.5 K, P = 1.50 atm: V = ?L
Answers
Explanation:
T = 409.5 K, P = 1.50 atm: V = 22.4 L The ideal gas law is: PV = nRT where. P = pressure. V = volume n = number of moles.
How many moles are in 825 atoms of carbon?
Answers
1.37 × 10⁻²¹ mol C
General Formulas and Concepts:Math
Pre-Algebra
Order of Operations: BPEMDAS
Brackets Parenthesis Exponents Multiplication Division Addition Subtraction Left to RightChemistry
Atomic Structure
Using Dimensional AnalysisAvogadro's Number - 6.022 × 10²³ atoms, molecules, formula units, etc.Explanation:Step 1: Define
825 atoms C
Step 2: Identify Conversions
Avogadro's Number
Step 3: Convert
\(\displaystyle 825 \ atoms \ C(\frac{1 \ mol \ C}{6.022 \cdot 10^{23} \ atoms \ C} )\) = 1.36998 × 10⁻²¹ mol C
Step 4: Check
We are given 3 sig figs. Follow sig fig rules and round.
1.36998 × 10⁻²¹ mol C ≈ 1.37 × 10⁻²¹ mol C
many acid-base reactions a starting material with a net _____ charge is usually an acid while a starting material with a net _____ charge is often a base. multiple choice question.
Answers
In many acid-base reactions, a starting material with a net Positive charge is usually an acid while a starting material with a net Negative charge is often a base.
In many acid-base reactions, a starting material with a net positive charge is usually an acid, while a starting material with a net negative charge is often a base. Acids are substances that can donate protons (H+) and are therefore positively charged when they lose a proton. Bases, on the other hand, can accept protons (H+) and tend to have a net negative charge when they gain a proton. This is based on the concept of proton transfer in acid-base reactions, where the acid donates a proton (positive charge) to the base, resulting in the formation of a new acid and base. It's important to note that not all acids or bases have a net charge, as their acidity or basicity can also be determined by other factors such as electron pair donation or acceptance.
learn more about acid-base reactions here:
https://brainly.com/question/3911136
#SPJ11
1. How many grams of NaOH are contained in 5.0 x 10^2mL of a 0.74 M sodium hydroxide solution?
a. 15 g
b. 74 g
c. 0.37 g
d. 30 g
e. 370g
Answers
Explanation because it’s A
if the equilibrium partial pressure of no2 is 0.053 atm and the equilibrium partial pressure of n2o4 is 1.28 atm at 25°c, what is the kp value for the reaction at 25°c?
Answers
Kp value for the reaction at 25°C is approximately 456.03. To solve for the Kp value, we can use the equation:
Kp = (P(NO2))^2 / P(N2O4)
Substituting the given values, we get:
Kp = (0.053)^2 / 1.28
Kp = 0.0022
Therefore, the Kp value for the reaction at 25°C is 0.0022.
To calculate the Kp value for the reaction at 25°C, we first need to identify the balanced chemical equation for the reaction:
2 NO2 (g) ⇌ N2O4 (g)
Next, we'll use the given equilibrium partial pressures:
NO2 = 0.053 atm
N2O4 = 1.28 atm
Now, we can calculate the Kp value using the formula:
Kp = [N2O4] / [NO2]^2
Substitute the values:
Kp = (1.28) / (0.053)^2
Kp ≈ 456.03
The Kp value for the reaction at 25°C is approximately 456.03.
To know more about equilibrium partial pressures: brainly.com/question/14928532
#SPJ11
Which of the following changes to sugar is An example of a physical change?
Answers
Answer:
burning it on the stove
Explanation:
help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!1
Answers
The compound that does not conform to the law of constant proportion law is is CO2 whose ratio by mass ought to be 8:3 and not 3:4.
What is the law of constant proportions?The law of constant proportions portrays the ideas that the composition of a pure sample of a substances has a fixed composition by mass.
Following the law of constant proportion, the compound that does not conform to this law is is CO2 whose ratio by mass ought to be 8:3 and not 3:4.
Learn more about constant proportions:https://brainly.com/question/20696665
#SPJ1
Answer:
your cool
Explanation:
what are the hybridization states for the c, n, and o atoms in the molecule ch2noh?
Answers
Answer:
calculate the formulae mass of mgs04 (c=12, fe=56, mg =24,s=32,0=16
In the molecule, CH₂NOH, the hybridization states of the carbon (C), nitrogen (N), and oxygen (O) atoms can be determined based on the number of sigma bonds and lone pairs around each atom. From this, the hybridization of Carbon (C) is sp³, the hybridization of Nitrogen (N) is sp² and the hybridization of oxygen is sp³ hybridized
Carbon (C): In CH₂NOH, the carbon atom is bonded to two hydrogen atoms and one oxygen atom. It also has one lone pair of electrons. Therefore, the carbon atom is sp³ hybridized.
Nitrogen (N): The nitrogen atom in CH₂NOH is bonded to one carbon atom and has two lone pairs of electrons. Hence, the nitrogen atom is sp² hybridized.
Oxygen (O): The oxygen atom in CH₂NOH is bonded to one carbon atom and one hydrogen atom. It also has two lone pairs of electrons. Thus, the oxygen atom is sp³ hybridized.
Hence, the hybridization of all the elements is given above.
Learn more about hybridization here:
https://brainly.com/question/32752412
#SPJ 4
which molecules can form a hydrogen bond with another identical molecule? hooh ch2ch2nh2 hi sih4 ch3ch2f
Answers
The molecules that can form hydrogen bonds with another identical molecule are HOOH (hydrogen peroxide), CH₃CH₂NH₂(ethylamine), and CH₃CH₂F (ethyl fluoride).
Hydrogen bonding occurs between a hydrogen atom bonded to an electronegative atom (such as oxygen, nitrogen, or fluorine) and another electronegative atom in a different molecule. Based on this criterion, the molecules that can form hydrogen bonds with another identical molecule are:
HOOH (Hydrogen peroxide): The oxygen atom in one molecule can form a hydrogen bond with the hydrogen atom in another molecule.CH₃CH₂NH₂ (Ethylamine): The nitrogen atom can form a hydrogen bond with the hydrogen atom in another ethylamine molecule.CH₃CH₂F (Ethyl fluoride): The fluorine atom can form a hydrogen bond with the hydrogen atom in another ethyl fluoride molecule.Learn more about Hydrogen Bond
brainly.com/question/30885458
#SPJ4
Quinone, an oxygenated hydrocarbon, is a chemical used in the photography industry. When a 0.144-g sample is analyzed by combustion analysis, 0.352 g of carbon dioxide and 0.0480 g of water are produced. Find the empirical formula for quinone.
Answers
Answer:
C3H2O1
Explanation:
The following data were obtained from the question:
Mass of compound = 0.144 g
Mass of CO2 = 0.352 g
Mass of H2O = 0.0480 g
Empirical formula of compound =?
Next, we shall determine the mass of carbon (C), hydrogen (H) and oxygen (O) present in the compound. This can be obtained as follow:
For carbon (C):
Molar mass of CO2 = 12 + (2×16)
Molar mass of CO2 = 44 g/mol
Mass of CO2 = 0.352 g
Mass of C in the compound
= 12/44 × 0.352
= 0.096 g
For Hydrogen (H):
Molar mass of H2O = (2×1) + 16
Molar mass of H2O = 18 g/mol
Mass of H2O = 0.0480 g
Mass of H in the compound
= 2/18 × 0.0480
= 0.0053 g
For oxygen (O):
Mass of O = mass of compound – (mass of C + mass of H)
Mass of compound = 0.144 g
Mass of C = 0.096 g
Mass of H = 0.0053 g
Mass of O = 0.144 – (0.096 + 0.0053)
Mass of O = 0.144 – 0.1013
Mass of O = 0.0427 g
Finally, we shall determine the empirical formula of the compound as follow:
C = 0.096 g
H = 0.0053 g
O = 0.0427 g
Divide both side by their molar mass
C = 0.096 / 12 = 0.008
H = 0.0053 / 1 = 0.0053
O = 0.0427 / 16 = 0.0027
Divide by the smallest
C = 0.008 / 0.0027 = 3
H = 0.0053 / 0.0027 = 2
O = 0.0027 / 0.0027 = 1
Therefore, the empirical formula of the compound is C3H2O1
Guys I need ur help I might as well just ask ur smarties for help ahah n yup I’ll be brainlisting;)
1) What have been the wider effect on the community of nuclear accidents? (Chernobyl)
Answers
Answer:
Hey sis
will you be my sis??
please give reply
I will be waiting
and fol.low.me
calculate the number of moles in positive and negative ions in 1.75 moles of calcium fluoride quizlet
Answers
CaF₂ ⇒ Ca²⁺ + 2F⁻
1.75 1.75 3.5
100 cm³ of a gas at 27°C is cooled to 20°C at constant pressure .Calculate the volume of gas at 20°C.
Answers
According to Charle's law, the volume of the given mass of a gas is directly proportional to its absolute temperature provided that the pressure is constant. Mathemically;
\(\begin{gathered} V\alpha T \\ V=kT \\ k=\frac{V}{T} \\ k=\frac{V_1}{T_1}=\frac{V_2}{T_2} \end{gathered}\)where;
V1 and V2 are the initial and final volume of the gas
T1 and T2 are the initial and final temperatures of the gas (in Kelvin)
Given the following parameters:
\(\begin{gathered} V_1=100\operatorname{cm}^3 \\ T_1=27^0C=27+273=300K \\ T_2=20^0C=20+273=293K \\ V_2=\text{?} \end{gathered}\)Substitute the given parameters into the formula;
\(\begin{gathered} V_2=\frac{V_1T_2}{T_1}^{} \\ V_2=\frac{100\times293}{300} \\ V_2=\frac{29300}{300} \\ V_2=\frac{293}{3} \\ V_2=97.67\operatorname{cm}^3 \end{gathered}\)Therefore the volume of the gas at 20°C is approximately 97.67cm³
An electromagnet is created by
A. putting a piece of soft iron in an outlet.
B. brushing a piece of steel with a soft cloth.
C. running electric current through a coiled, conductive wire.
D. rubbing two pieces of metal together quickly.
Answers
A. putting a piece of soft iron in an outlet
Question 1
1. Na2O + H20 --->
NaOH
A. Single Replacement
B. Double Replacement
c. Decomposition
D. Synthesis
E. Combustion
Answers
Answer: D. Synthesis
Explanation:
Sodium Oxide + Water = Sodium Hydroxide
PLEASE NO LINKS OR FILE SCAMS
what is the balanced equation for CuSO4 + 2NaOH → Cu(OH)2 + Na2SO4 I just want the answer please help
Answers
C6H12O6 + 6 O2(g) 6 CO2(g) + 6 H2O(g)
If 7.5 g of glucose react with 5.5 L of oxygen, which one is the limiting reagent?
Answers
C₆H₁₂O₆ + 6O₂ ---> 6CO₂ + 6H₂O, If 7.5 g of glucose react with 5.5 L of oxygen, the limiting reagent is glucose.
The balanced reaction is given as :
C₆H₁₂O₆ + 6O₂ ---> 6CO₂ + 6H₂O
mass of glucose = 7.5 g
molar mass of glucose = 180 g/mol
number of moles =mass / molar mass
= 7.5 / 180
= 0.041 mol
volume of oxygen = 5.5 L
density of oxygen = 1.42 g/ml
mass = density × volume
mass = 1.42 × 5.5
mass = 7.81
moles = mass / molar mass
= 7.81 / 32
= 0.244 mol
mass of reactant from each product:
now, glucose , mass of CO₂ = 0.041 × 6 × 44 = 10.84 g
oxygen, mass of CO₂ = 0.244 × 6 × 44 = 64.41 g
Since glucose gives the smaller amount of product glucose is a limiting reagent.
Thus, C₆H₁₂O₆ + 6O₂ ---> 6CO₂ + 6H₂O, If 7.5 g of glucose react with 5.5 L of oxygen, the limiting reagent is glucose.
To learn more about limiting reagent here
https://brainly.com/question/26905271
#SPJ1
what is the ratio of mass of 0.7moles of nitrogen gas to 11.2liters of oxigen gas at STP?
Answers
Answer:
if a 40.0-gram sample of the gas occupies 11.2 liters of space at STP? A balloon is filled with 5 moles of helium gas.
Explanation:
how much heat energy is required to boil 66.7 g of ammonia, nh3? the heat of vaporization of ammonia is 327 cal/g.
Answers
We may use the following formula to determine the thermal energy necessary to boil 66.7 g of ammonia m Q = m H vap where Q is the heat energy, m is the mass of the vaporized material.
and H vap is the heat of vaporization. When we substitute the provided values, we get: Q = 66.7 g 327 calories per gram Q = 21800.9 cal The heat energy required to boil 66.7 g of ammonia is thus 21800.9 cal. We may use the following formula to determine the thermal energy necessary to boil 66.7 g of ammonia m Q = m H vap where Q is the heat energy, m is the mass of the vaporized material. heat energy is required to boil 66.7 g of ammonia, nh3? the heat of vaporization of ammonia is 327 cal/g.
learn more about heat here:
https://brainly.com/question/1429452
#SPJ4
The first noble gas with a Lewis Structure with 8 dots is
A. Ar
B. Kr
C. He
D. ne
Answers
Answer:
C) He
Explanation:
Helium is one of the noble gases and contains a full valence shell. Unlike the other noble gases in Group 8, Helium only contains two valence electrons.
measurements show that unknown compound x has the following composition: element mass % zinc 75.5% oxygen 24.7% write the empirical chemical formula of x.
Answers
The empirical formula of a compound is ZnO.
The empirical formula of a compound is the simplest formula that shows the relative number of atoms of each element in the compound.
To find the empirical formula of compound X, we first need to convert the mass percentages to moles. The mass of zinc in 100 g of compound X is 75.5 g, and the molar mass of zinc is 65.38 g/mol. This means that there are 0.115 moles of zinc in 100 g of compound X.
The mass of oxygen in 100 g of compound X is 24.7 g, and the molar mass of oxygen is 16 g/mol. This means that there are 1.54 moles of oxygen in 100 g of compound X.
The ratio of the number of moles of zinc to the number of moles of oxygen is
0.115 / 1.54 = 0.074.
This means that the empirical formula of compound X is Zn0.074O, or ZnO.
Therefore, the empirical formula of compound X is ZnO.
Learn more about empirical formula,here:
https://brainly.com/question/32125056
#SPJ12
What would be the new pressure if 250cm3 of gas at standard pressure is compressed to a volume of 150 cm3
Answers
Answer:
5/3 or 1 2/3 atmospheres.
Explanation:
If the temperature is kept constant then P*V will be constant.
The standard pressure is 1 Atm. so:
250 * 1 = 150 * V
V = 250 / 150
= 5/3 Atm.
The new pressure of gas is 126.66 mm Hg at constant temperature according to Boyle's law.
What is Boyle's law ?
Boyle's law is an experimental gas law which describes how the pressure of the gas decreases as the volume increases. It's statement can be stated as, the absolute pressure which is exerted by a given mass of an ideal gas is inversely proportional to its volume provided temperature and amount of gas remains unchanged.
Mathematically, it can be stated as,
P∝1/V or PV=K. The equation states that the product of of pressure and volume is constant for a given mass of gas and the equation holds true as long as temperature is maintained constant.
According to the equation the unknown pressure and volume of any one gas can be determined if two gases are to be considered.That is,
P₁V₁=P₂V₂
∴P₂=760×250/150=126.66 mm Hg
Therefore, the final pressure of the gas is 126.66 mm Hg.
Learn more about Boyle's law,here:
https://brainly.com/question/1437490
#SPJ2
select all the statements that describe the reaction of water with an alkyne in the presence of an acid catalyst. multiple select question. the initial product of the reaction is an enol. hgso4 is used as an additional catalyst in this reaction. the enol form of the product is more stable than the keto form. the ketone form of the product is more stable than the enol form. the enol tautomerizes to form a ketone.
Answers
The statements that describe the reaction of water with an alkyne in the presence of an acid catalyst are-
The initial product of the reaction is an enol.HgSO4 is used as an additional catalyst in this reaction.The enol tautomerizes to form a ketone.What is alkyne?An alkyne is a type of hydrocarbon that contains a carbon-carbon triple bond. It is a unsaturated hydrocarbon and belongs to the alkene functional group. Alkynes have the general molecular formula of CnH₂n-2. They are characterized by their linear structure and high reactivity due to the presence of the triple bond. Alkynes are commonly used in organic synthesis and are important building blocks in the production of various chemicals and materials.
The incorrect statements are:
The enol form of the product is more stable than the keto form.
The ketone form of the product is more stable than the enol form.
The stability of the enol and keto forms can vary depending on the specific compounds involved in the reaction.
To know more about alkynes, click here:
https://brainly.com/question/30901211
#SPJ4