1. A neutron in a reactor makes an elastic headon collision with the nucleus of an atom initially at rest.
Assume: The mass of the atomic nucleus is
about 11.4 the mass of the neutron.
What fraction of the neutron’s kinetic energy is transferred to the atomic nucleus?

2. If the initial kinetic energy of the neutron is
5.43 × 10−13 J, find its final kinetic energy.
Answer in units of J.

The energy an object has due to its motion is called kinetic energy.

Mars is believed to have significantly less metal in its core than Earth due to its smaller size and differences in planetary formation processes.

Mars and Earth formed around the same time, approximately 4.6 billion years ago, through the process of accretion. However, their formation processes differed in some aspects, resulting in variations in their compositions. Mars is smaller than Earth, with a diameter of about 6,779 kilometers, compared to Earth's 12,742 kilometers. Due to its smaller size, Mars has a lower mass and gravity, which could have led to a lower concentration of heavy metals sinking into its core during formation.

Additionally, the abundance of metal-rich meteorites and other materials available during the formation of the two planets may have been different. Earth may have received more metal-rich materials due to its larger size and stronger gravitational pull, whereas Mars, being farther from the Sun, may have had less access to these building blocks.

Another factor is the differentiation process that both planets underwent. Earth's core is believed to have separated more efficiently from its mantle, leading to a higher concentration of heavy metals in its core. Mars, on the other hand, may have experienced a less efficient differentiation process, resulting in a less metal-rich core.

In summary, Mars's smaller size, differences in planetary formation, and less efficient differentiation process contribute to its core containing significantly less metal than Earth's core.

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Answer:

waxing gibbous

Explanation:

because the moon is before the earth

1. The top 5 countries for gas flaring in the world in 2016 were Russia, Iraq, Iran, the United States, and Algeria. The top 5 ranking did not change between 2012 and 2016.

Based on the data from the "bcmox" column in the provided shapefile for 2016, a map can be created to visualize the distribution of flared gas. By analyzing the values, it can be determined that Russia, Iraq, Iran, the United States, and Algeria were the top 5 countries with the highest gas flaring in 2016.

These countries had the highest amounts of billion cubic meters of flared gas. The ranking remained the same compared to 2012, indicating that these countries have consistently been significant contributors to gas flaring over time. This highlights the need for targeted interventions and policies to address this issue in these regions.

2. The bottom 5 countries for access to electricity in the world in 2012 were Burundi, Chad, Central African Republic, South Sudan, and Sierra Leone. Considering the distribution of gas flares globally, a suggestion to a policy maker in a country interested in expanding electricity access would be to prioritize the adoption of cleaner and more sustainable energy sources.

By investing in renewable energy technologies such as solar, wind, or hydroelectric power, the country can reduce its reliance on fossil fuels and minimize the need for gas flaring. This approach would not only help expand electricity access but also contribute to mitigating climate change and reducing the negative health effects associated with gas flaring in surrounding communities.

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Answer:

the answer is C ----- it is the rate of change of velocity per unit time

Explanation:

acceleration

\( = \frac{velocity(v)}{time(t)} \)

Answer:

A and d

Explanation:

Answer:

answer in picture

Explanation:

Answer:

Initial velocity (u) = 40 m/s

Distance travel in last 5 seconds = 100 m

Explanation:

Given:

Acceleration (a) = 8 m/s²

Final velocity (v) = 0 m/s

Find;

1] Initial velocity before 5 sec

2] Distance travel in last 5 seconds

Computation:

1] Initial velocity before 5 sec

v = u + at

0 = u + (-8)(5)

u - 40 = 0

Initial velocity (u) = 40 m/s

2] Distance travel in last 5 seconds

s = ut + (1/2)(a)(t²)

s = (40)(5) + (1/2)(-8)(5²)

s = 200 - 100

Distance travel in last 5 seconds = 100 m

Answer:

8.19 kg m/s

Explanation:

The change in momentum is equal to the impulse. This impulse is also calculated as the force times time, so

Then, replacing F = 39 N and t = 0.21 s, we get:

So, the change in momentum of the tennis ball is 8.19 kg m/s

There will be a nine times increase in the gravitational pull between them. Because the separation between two objects of equivalent mass is fixed. if each thing had a mass that was treble what it is now.

Regardless of whether two objects have equivalent masses or not, the gravitational force will pull them together.

Given is the gravitational force between two objects: F = G m1 m2/r2, where m1 is the mass of the first object, m2 is the mass of the second object, and r is the distance between the two objects.

F = G m2/r2 represents the gravitational force between the objects with respect to m1 and m2.

The Last Case

The new gravitational force between the objects, m1 = m2 = 3 m, is represented as F' = G (3m)2/r2.

F' = 9 G m²/r²

F' = 9 F

gravitational force between the objects is given as

F = G m²/r²

Final Case :

m₁ = m₂ = 3 m

new gravitational force between the objects is given as

F' = G (3m)²/r²

F' = 9 G m²/r²

F' = 9 F

hence the gravitational force between the two objects becomes 9 times.

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The final kinetic energy of the skateboarder after she freewheels and did work against friction on the flat section of the path is 4,600 J.

The final kinetic energy of the stakeboarder is determined by applying the principle of conservation of energy as shown below;

ΔK.E = -W

K.Ef - K.Ei = -W

where;

K.Ef = K.Ei - W

K.Ef = 5,000 J - 400 J

K.Ef = 4,600 J

Thus, the final kinetic energy of the skateboarder is 4,600 J.

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Answer:

The student that says the phrase "travels through liquids" goes in the middle, in between the two circles in the venn diagram.

Explanation:

To be effective, there must be must agreement aimed at preventing or reducing ozone depletion by the international government and the various international organizations.

It can be defined as the origination of the contaminant substance that poisonous or harmful to our natural environment.

The Montreal Protocol is an international agreement that was established to safeguard the earth's atmosphere by gradually banning the manufacturing and use of chemicals that damage the ozone layer (ODS).

Thus, For an agreement between the different international organizations and the international government to be effective, it must be targeted at avoiding or mitigating ozone depletion.

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A skater is rotating with her arms stretched out away from her body. As she pulls her arms in towards her body, her angular velocity increases.

If she pulls her arms in towards her body, moment of inertia reduces. And her angular momentum is conserved.

According to the law of conservation of angular momentum, we can say that, in the absence of external torque, the angular momentum of a system of particles does not change.

So, as she reduces her moment of inertia, her angular velocity increases. This results in the increase of her spinning speed.

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Answer:

In biology, cell theory is the historic scientific theory, now universally accepted, that living organisms are made up of cells, that they are the basic structural/organizational unit of all organisms, and that all cells come from pre-existing cells. Cells are the basic unit of structure in all organisms and also the basic unit of reproduction.

Explanation:

The three tenets to the cell theory are as described below:

All living organisms are composed of one or more cells.

The cell is the basic unit of structure and organization in organisms.

Cells arise from pre-existing cells.

There is no universally accepted definition of life. Some biologists consider non-cellular entities such as viruses living organisms,[1] and thus reasonably disagree with the first tenet. Throughout this article, it will lead you through the history of cell theory, how the discovery of cells was made possible, what the cell theory has become today and background information and history regarding other opposing concepts of cell theory.

Answer:

B

Explanation:

because that's the answer

Answer:

hydrochlorine +12÷B to the power of 4 -× y reapeated zminus 2 to the power of 9

Starburst galaxies is simply known as the rate at which the galaxy is now converting gas into stars. The statement that is not a general characteristic of starburst galaxies is that The "starburst" is thought to be caused by the presence of a supermassive black hole in the galaxy's center.

They are known to be rare. A starburst is known to be an astrophysical process. It is the process of star formation happening at a rate that is large when compared to the rate that is often observed.

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Which is not a general characteristic of starburst galaxies?

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According to the statement, the vapor pressure of the NaCl solution is 22.63 torr.

To calculate the vapor pressure of the NaCl solution, we need to first calculate the mole fraction of water in the solution:

moles of water = mass of water / molar mass of water

moles of water = 150.0 g / 18.015 g/mol = 8.32 mol

moles of NaCl = mass of NaCl / molar mass of NaCl

moles of NaCl = 20.0 g / 58.44 g/mol = 0.342 mol

total moles = moles of water + moles of NaCl = 8.32 mol + 0.342 mol = 8.662 mol

X(water) = moles of water / total moles = 8.32 mol / 8.662 mol = 0.9603

Next, we can use Raoult's law to calculate the vapor pressure of the solution:

P = X(water) * P°(water)

Where P°(water) is the vapor pressure of pure water, which is given as 23.56 torr.

P = 0.9603 * 23.56 torr = 22.63 torr

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The angle that the swimmer must orient himself at can be calculated using basic mechanics as follows: (roughly west of north.)

Can a swimmer use velocity V to swim in still water?

A swimmer can swim at speed v in calm water and at speed v2 in a river that is flowing. He should swim making an angle with the upstream in order to cross the river in the smallest amount of time.

What is the source of the river's enquiring town's response?

The town of Curious Town is really unusual. The frog goes up a tree in the town, the puppies meow, the kitten barks, the river is flowing, and the volcano is covered in dew. There are more than eight hues in the rainbow in the strange town, yet only two in a week.

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The g - string will stretch by 0.0016 mm.

We have a g - string of a guitar with given specifications.

We have to determine how many mm does a 75-cm-long g - string stretch when it’s first tuned.

According to the question -

The force of tension in the string -

\($v = \sqrt{\frac{T}{\mu} }\)

T = \($v^{2} \mu\) = 250 x 250 x 0.0011 = 68.75 N

The Yung modulus of steel = 2 x \(10^{11}\) N/\(m^{2}\)

the amount by which the g - string will be stretched is given by -

\($\delta L = \frac{LT}{Y(\pi r^{2})}\)

Substituting the values -

\($\delta L = \frac{0.75\times 68.75 }{(2\times 10^{11} )\times (\pi (2.2 \times 10^{-4}\times 2.2\times 10^{-4}) )}\)

\(\delta L=\) 0.0016mm

Hence, the g - string will stretch by 0.0016 mm.

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[ The given question is incomplete. The complete question is

" The G string on a guitar is a 0.46-mm-diameter steel string

with a linear density of 1.1 g/m. When the string is properly

tuned to 196 Hz, the wave speed on the string is 250 m/s. Tuning

is done by turning the tuning screw, which slowly tightens—and

stretches—the string. By how many mm does a 75-cm-long G

string stretch when it’s first tuned? "]

Answer:

I would include extra insulation, a heating system, and some snug-fitting sweaters.

Explanation:

that way i won't get cold

\(^{-1}\)The shift in acetylferrocene IR is due to the addition of the acetyl group to the ferrocene molecule.

The acetyl group introduces new functional groups, specifically a carbonyl group (C=O), which causes a shift in the IR spectrum. This shift can be seen in the stretching vibrations of the carbonyl group, which typically occur in the range of 1650-1750 cm\(^{-1}\). The presence of the acetyl group also affects the aromatic ring vibrations, causing shifts in the IR spectrum in the range of 1400-1600 cm. These shifts are due to the change in the electronic environment of the ferrocene molecule, which affects the vibrational frequencies of the functional groups.

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The magnitude of gravitational force acting on the space junk by the satellite is determined by the masses of the objects and the distance between them.

To calculate the magnitude of the gravitational force acting on the space junk by the satellite, you need to use the formula for gravitational force: F = G × (m1 × m2) / r² where: - F is the gravitational force, - G is the gravitational constant (approximately 6.674 × 10⁻¹¹ N m²/kg²), - m1 and m2 are the masses of the satellite and space junk, respectively, - r is the distance between the centers of mass of the satellite and space junk.

The larger the masses and the closer the objects are, the stronger the gravitational force. However, it is important to note that space junk is typically not in orbit around a satellite and therefore not subject to its gravitational force. Instead, space junk is affected by the gravitational force of the Earth and other celestial bodies, as well as other forces such as atmospheric drag and solar radiation pressure.

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Answer:

B - Person A's chair rolls backwards.

Explanation:

This can be seen simply through the Conservation of Momentum. When the ball is thrown to be, the ball's momentum(+m) is transfererd to B, so B's chair moves forward(think about it - it makes sense, doesn't it?), meaning A's chair moves backwards.

So, B.

EXTRA TIP: Try drawing a diagram to help you!  

The question is not complete. The complete question is :

During a certain period of time, the angular position of a rotating object is given by \($\theta =2t^2 +10t+5$\), where θ is in radians and t is in seconds.  Determine the angular position, angular speed, and angular acceleration of the door (a) at t = 0.00 seconds, (b) at t = 3.00 seconds.

Solution :

Given :

Displacement or angular position of the object, \($\theta =2t^2 +10t+5$\)

∴ Angular speed is   \($\omega = \frac{d \theta}{dt}$\)

                                 ω = 10 + 4t

And angular acceleration is \($\alpha = \frac{d \omega}{dt}$\)

                                              α = 4

a). At time, t = 0.00 seconds :

   Angular displacement is \($\theta =2t^2 +10t+5$\)

                                            \($\theta =2(0)^2 +10(0)+5$\)

                                               = 5 rad

  Angular speed is  ω = 10 + 4t

                                 ω = 10 + 4(0)

                                     = 10 rad/s

Angular acceleration is α = 4 \($rad/s^2$\)

b). At time, t = 3.00 seconds :

   Angular displacement is \($\theta =2t^2 +10t+5$\)

                                            \($\theta =2(3)^2 +10(3)+5$\)

                                               = 53 rad

  Angular speed is  ω = 10 + 4t

                                 ω = 10 + 4(3)

                                     = 22 rad/s

Angular acceleration is α = 4 \($rad/s^2$\)

Answer:

1226.8

I hope this helps!!!

The Acceleration of the system is 6.41 m/s².

Given,

α= 15°, m₁ = 7kg

β= 65°, m₂ = 11 kg

Let, a be the acceleration and T is the tensions at the end it's the cord.

Let, the mass m₂ be coming down along the inclined plane along the inclined surface towards downward m₂g sin β and the tension in the upward direction,

Resultant force, m₂a=m₂g sin β -T

11a=((11) ×g sin 65°) -T  ...(i)

Now, considering the motion of m₁ which moves downwards, the forces are m₁g sinα, and T both are acting downwards.

Resultant force m₁a = m₁g sin α+T

7a =7g sin 15°+T  ...(ii)

Solving both the equations by adding them,

18a=11gsin 65°+7g sin 15°-T+T

18a=11gsin 65°+7g sin 15°=115.45

a=115.45/18=6.41 m/s²

Hence, the Acceleration of the system is 6.41 m/s².

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Explanation:

Newton's first law states that if a body is at rest or moving at a constant speed in a straight line, it will remain at rest or keep moving in a straight line at constant speed unless it is acted upon by a force.

Example a ball at rest remains at rest unless a net force is act on it. If u kick that ball, net force will act on it

This is why we called motion of inertia

Velocity of Deidre and her dog is 2.11m/s.

=2.11m/s

Thus , we can conclude that the velocity of Deidre and her dog is 2.11 m/s towards north .

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