1) 4/10=
2) 2/3=
3) 5/10=
4) 3/8=
5) 2/11 =
6) 3/7 =
7) 1/6 =
8) 4/6 =
9) 11/12 =
10) 1/4 =
Answers
2) 2/3 = 0.666666... (repeating decimal) or 66.67% (rounded to two decimal places)
3) 5/10 = 1/2
4) 3/8 = 0.375 or 37.5%
5) 2/11 = 0.181818... (repeating decimal) or approximately 18.18% (rounded to two decimal places)
6) 3/7 = 0.428571... (repeating decimal) or approximately 42.86% (rounded to two decimal places)
7) 1/6 = 0.166666... (repeating decimal) or approximately 16.67% (rounded to two decimal places)
8) 4/6 = 2/3
9) 11/12 = 0.916666... (repeating decimal) or approximately 91.67% (rounded to two decimal places)
10) 1/4 = 0.25 or 25%
Related Questions
At a dog shelter, a 28-pound bag of dog food will feed 42 dogs. How many dogs would you expect to feed with a 14-pound bag of dog food? (Input only whole numbers.)
Pounds of Dog Food 14 28 56
Number of Dogs Fed ? 42 84
Answers
Answer: A 14-Pound bag will feed 21 dogs.
Step-by-step explanation: Because 14 is half of 28 all you need to do is divide 42 by 2 like this 42/2=21 you can check your answer by adding the answer twice like this 21+21=42
Answer:
its 21 good day
Step-by-step explanation:
Solve each proportion. Round your answer to the nearest tenth, if necessary.
4/x=7/6
Answers
\(\frac{4}{x}=\frac{7}{6}\\\\\frac{x}{4}=\frac{6}{7}\\\\x=\frac{24}{7}\\\\x \approx \boxed{3.4}\)
The answer is:
x = 3.4
Work/explanation:
To solve a proportion, I will cross multiply:
\(\sf{\dfrac{4}{x}=\dfrac{7}{6}}\)
4 times 6 and 7 times x:
\(\sf{24=7x}\)
Divide each side by 7:
\(\sf{3.4=x\)
I have rounded the answer to the nearest tenth.
Hence, x = 3.4,all the answer i ask
Answers
Answer:
fortnite
Step-by-step explanation:
fo+rtni+te=fortnite
A remedial program evenly enrolls tradition and non-traditional students. If a random sample of 4 students is selected from the program to be interviewed about the introduction of a new on-line class, what is the probability that 3 students selected are traditional students
Answers
The probability of selecting 3 students who are traditional students is:P (3 students are traditional students) = 0.5 * 0.5 * 0.5 * 0.5 + 0.5 * 0.5 * 0.5 * 0.5 + 0.5 * 0.5 * 0.5 * 0.5 + 0.5 * 0.5 * 0.5 * 0.5= (4 * 0.5 * 0.5 * 0.5 * 0.5)= 0.25 Hence, the probability of selecting 3 students who are traditional students is 0.25.
A remedial program offers traditional and non-traditional students equal enrollment. If a random sample of 4 students is selected from the program to be interviewed about the introduction of a new online class, the probability of selecting 3 students who are traditional students is calculated below.
P (3 students are traditional students)P (1st student is traditional) * P (2nd student is traditional) * P (3rd student is traditional) * P (4th student is non-traditional) + P (1st student is traditional) * P (2nd student is traditional) * P (3rd student is non-traditional) * P (4th student is traditional) + P (1st student is traditional) * P (2nd student is non-traditional) * P (3rd student is traditional) * P (4th student is traditional) + P (1st student is non-traditional) * P (2nd student is traditional) * P (3rd student is traditional) * P (4th student is traditional).We know that a remedial program offers traditional and non-traditional students equal enrollment. Therefore, the probability that a student is traditional is 0.5.
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Consider the function f(x) = x2 - 4x + 8 on the interval 0, 4. Verify that this function satisfies the three hypotheses of Rolle's Theorem on the inverval f(x) is f(x) is and f(0) on [0, 4] on (0, 4) f(4) Then by Rolle's theorem, there exists at least one value c such that f'(c) = 0. Find all such values c and enter them as a comma-separated list. Values of c =: (1 point) Consider the function graphed below. P n ? Does this function satisfy the hypotheses of the Mean Value Theorem on the interval a, b ? Does it satisfy the conclusion?? f(b) f(a)2 At what point c is f'(c) b - a
Answers
Verifying that this function satisfies the three hypotheses of Rolle's Theorem on the inverval f(x) is f(x) is and f(0) on [0, 4] on (0, 4) f(4) Then by Rolle's theorem, there exists at least one value c = 2 such that f'(c) = 0.
Given:
Consider the function f(x) = x2 - 4x + 8 on the interval 0, 4. Verify that this function satisfies the three hypotheses of Rolle's Theorem on the inverval f(x) is f(x) is and f(0) on [0, 4] on (0, 4) f(4) Then by Rolle's theorem, there exists at least one value c such that f'(c) = 0.
f(x)=x^2−4x+8, [0,4]
when, x = 0
f(x) = x^2 -4x +8
f(0) = y = 0 - 0 + 8 = 8
when, x=4
f(5) = y = 16 - 16+8 =
thus, we have 2 points (0, 8) ; (4, 8)
slope,m = {8-(8)} / {4-0} = 0
hence, we have to calculate all the points,x where 0<x<8 and slope=0
f '(x) = 2x - 4 = 0
or, f '(c) = 2c - 4 = 0
c = 4/2 =2 ( 0<x<4)
hence, the there is only one solution c=2 which satisfies Rolle's theorem.
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There is grass growing on top of all the layers, yet there are remains of sea life below, how is that possible?
Answers
Hope this helps!
Triangle Proofs: SAS, SSS, ASA, AAS & HL B Given: 1. D C is the midpoint of BE ZBACZEDC Prove: A А to E AABC = ADEC Statements Reasons
Answers
Answer:
Either AAA or ASA
Step-by-step explanation:
Two angels are the same and the lengths that are considered are the same.
A particle of mass mm moves in the plane with coordinates ( x ( t ) , y ( t ) )(x(t),y(t)) under the influence of a force that is directed toward the origin and has magnitude k / \left( x ^ { 2 } + y ^ { 2 } \right)k/(x 2 +y 2 )—an inverse-square central force field.
Answers
An inverse-square central force field is \(mx^{''} = -\frac{kx}{r^3}\\ \\mx^{''} = -\frac{ky}{r^3}\\\).
From Newton's second law of motion,
mass × acceleration = Force acting on the mass
Resolving the force F along x and y directions and applying Newton's second law of motion,
Using,
\(r = \sqrt{x^2+y^2}\)
Therefore,
\(m\frac{d^2x}{dt^2} =-|F|cos \theta\)
\(mx^{''} = -\frac{k}{x^2+y^2} \frac{x}{\sqrt{x^2+y^2} } \\\\mx^{''} = - \frac{kx}{(x^2+y^2)^\frac{3}{2} }\\ \\mx^{''} = - \frac{kx}{r^3}\)
Where \(r = \sqrt{x^2+y^2}\)
and cosθ = \(\frac{x}{\sqrt{x^2+y^2} }\)
Similarly using,
\(r = \sqrt{x^2+y^2}\)
we get,
\(m\frac{d^2y}{dt^2} = -|F|sin\theta\)
\(mx^{''} = -\frac{k}{x^2+y^2} \frac{x}{\sqrt{x^2+y^2} } \\\\mx^{''} = - \frac{kx}{(x^2+y^2)^\frac{3}{2} }\\ \\mx^{''} = - \frac{kx}{r^3}\)
Where \(r = \sqrt{x^2+y^2}\)
and sinθ = \(\frac{y}{\sqrt{x^2+y^2} }\)
Therefore we showed that holds
\(mx^{''} = -\frac{kx}{r^3}\\ \\mx^{''} = -\frac{ky}{r^3}\\\)
Hence the answer is an inverse-square central force field is \(mx^{''} = -\frac{kx}{r^3}\\ \\mx^{''} = -\frac{ky}{r^3}\\\).
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new spark plugs have just been installed in a small airplane with a two-cylinder engine. for each spark plug, the probability that it is defective and will fail during its first 20 minutes of flight is 1/2,000, independent of the other spark plugs.(a) for any given spark plug, what is the probability that it will not fail during the first 20 minutes of flight? (round your answer to four decimal places.)0.9995 correct: your answer is correct.(b) what is the probability that none of the two spark plugs will fail during the first 20 minutes of flight? (round your answer to four decimal places.)0.0010 incorrect: your answer is incorrect.(c) what is the probability that at least one of the spark plugs will fail? (round your answer to four decimal places.)
Answers
Using the binomial distribution, the probabilities are given as follows:
a) Any spark plug not failing during the flight: 0.9995.
b) None of the two failing during the flight: 0.9990.
c) At least one of the two failing during the flight: 0.0010.
Binomial distributionThe mass function of the binomial probability distribution is given as follows:
\(P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}\)
\(C_{n,x} = \frac{n!}{x!(n-x)!}\)
In which the parameters are as follows:
n is the number of trials of the experiment.p is the probability of a success on a single trial of the experiment.The values of these parameters are given as follows:
p = 1/2000 = 0.0005, n = 2.
Hence the probability that a single spark plug will not fail is given as follows:
1 - 0.0005 = 0.9995.
The probability that none fail is:
P(X = 0) = (0.9995)² = 0.9990.
The probability that at least one fails is given as follows:
1 - 0.9990 = 0.0010.
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I neee help plz
Solve by factoring.
5c^2 - 31c= 28
The solution is c=
(Simplify your answer.
Answers
the answer is,
\(c(5c - 31)\)
Find the mean, the median, and the mode(s), if any, for the given data. Round noninteger means to the nearest tenth. (If there ismore than one mode, enter your answer as a comma-separated list. If an answer does not exist, enter DNE.-8.1, -2.4, 4.7, 4.7, 6.6, 8.3, 9.5meanmedianmode(s)
Answers
Given: The data below
\(-8.1,-2.4,4.7,4.7,6.6,8.3,9.5\)To Determine: The mean, median and mode of the given data
Solution
The mean of a set of data is given by the formula
\(\begin{gathered} mean=\frac{\Sigma x}{n} \\ \Sigma x=summation\text{ of all the numbers given} \\ n=number\text{ of numbers given} \end{gathered}\)Apply the formula to calculate the mean of the given data
\(mean=\frac{-8.1+(-2.4)+4.7+4.7+6.6+8.3+9.5}{7}\)\(\begin{gathered} mean=\frac{-8.1-2.4+4.7+4.7+6.6+8.3+9.5}{7} \\ mean=\frac{23.3}{7} \\ mean=3.32857 \\ mean\approx3.3 \end{gathered}\)Calculate the median
Re-arrange the data in ascending order
\(-8.1,-2.4,4.7,4.7,6.6,8.3,9.5\)Locate the middle number
There are seven number from position 1st to 7th.
The middle number is the number in the 4th position
From the above, the 4th number
Pls help! I will give brainliest!
Answers
Answer: the answer is: A student needs to take 10 dance classes to learn the routine.
Step-by-step explanation: 7 1/2 DIVIDED by 3/4=10
//Give thanks(and or Brainliest) if helpful (≧▽≦)//
A bicycle repair shop offers two service packages to its customers: a tune up or a complete overhaul, which includes the tune up plus some additional services. All bicycles go through wheel balancing before leaving the shop. The repair shop is open 60 hours per week and receives an average of 180 bicycles each week. The shop employs three "tune up" technicians, one "additional services" technician, and two wheel balancing" specialists. Past data indicates that 25% of customers opt for the "additional services" option. Wheel Tune Up Balancing T = 75 T= 20 minutes minutes Additional Services T = 72 minutes a) Create a demand matrix for this process b) What will be the daily capacity at each stage of the process? c) Find the implied utilizations for each stage of the process. d) What will be the weekly capacity of the process? e) Is the flow rate of this process capacity-constrained or demand-constrained?
Answers
A bicycle repair shop that offers two service packages: a tune-up and a complete overhaul.
The shop operates for 60 hours per week and receives an average of 180 bicycles each week. To analyze the capacity and utilization of the process, we need to consider the time taken at each stage and the demand for each service option. We'll break down the problem into multiple parts and provide a detailed explanation using mathematical terms.
a) Creating the Demand Matrix:
To create a demand matrix, we need to determine the number of bicycles going through each stage of the process. Let's denote the demand for tune-up as T and the demand for additional services as A.
Given that the average number of bicycles received per week is 180 and 25% of customers opt for additional services, we can calculate the demands as follows:
Demand for tune-up (T) = Total demand - Demand for additional services
T = 180 - (0.25 * 180)
T = 180 - 45
T = 135
Demand for additional services (A) = 0.25 * Total demand
A = 0.25 * 180
A = 45
Now, we can create a demand matrix based on the demand for each service option:
Demand Matrix:
Tune-up Additional Services Wheel Balancing
Tune-up [135 0 0]
Additional [0 45 0]
Services
Total [ 135 45 0 ]
The demand matrix shows the number of bicycles flowing through each stage of the process.
b) Daily Capacity at Each Stage:
To calculate the daily capacity at each stage, we need to consider the time taken for each service option. Given that the shop operates for 60 hours per week, we can calculate the daily capacity at each stage:
Tune-up technician time per bicycle (\(T_{tuneup}\)) = 75 minutes
Additional services technician time per bicycle (\(T_{additional}\)) = 72 minutes
Wheel balancing specialist time per bicycle (\(T_{balancing}\)) = 20 minutes
Daily Capacity (C) = (60 hours * 60 minutes) / (\(T_{tuneup}\) + \(T_{additional}\) + \(T_{balancing}\))
Substituting the given values:
C = (60 * 60) / (75 + 72 + 20)
C = 21600 / 167
C ≈ 129.34 bicycles per day
Therefore, the daily capacity at each stage of the process is as follows:
Tune-up: 129 bicycles per day
Additional Services: 129 bicycles per day
Wheel Balancing: 129 bicycles per day
c) Implied Utilizations:
To find the implied utilizations, we need to compare the demand and the capacity at each stage of the process. Utilization can be calculated as the demand divided by the capacity.
Implied Utilization (U) = Demand / Daily Capacity
For the Tune-up stage:
\(U_{tuneup}\) = 135 / 129 ≈ 1.05
For the Additional Services stage:
\(U_{additional}\) = 45 / 129 ≈ 0.35
For the Wheel Balancing stage:
\(U_{balancing}\) = 0 / 129 = 0
The implied utilizations show how efficiently each stage of the process is being utilized. Utilization values greater than 1 indicate that the stage is operating beyond its capacity.
d) Weekly Capacity of the Process:
To calculate the weekly capacity of the process, we multiply the daily capacity by the number of days the shop is open per week:
Weekly Capacity = Daily Capacity * Number of days shop is open per week
Given that the shop is open for 60 hours per week, the number of days the shop is open per week can be calculated as follows:
Number of days shop is open per week = 60 hours / 24 hours per day = 2.5 days
Therefore, the weekly capacity of the process is:
Weekly Capacity = Daily Capacity * Number of days shop is open per week
Weekly Capacity = 129 bicycles per day * 2.5 days
Weekly Capacity = 322.5 bicycles per week
e) Flow Rate and Constraint Analysis:
To determine if the flow rate of the process is capacity-constrained or demand-constrained, we compare the weekly capacity to the demand for each service option.
Demand for Tune-up (\(T_{demand}\)) = 135 bicycles per week
Demand for Additional Services (\(A_{demand}\)) = 45 bicycles per week
Comparing the demands with the weekly capacity:
\(T_{demand}\) < Weekly Capacity (135 < 322.5)
\(A_{demand}\) < Weekly Capacity (45 < 322.5)
Since both the demands for tune-up and additional services are less than the weekly capacity, the flow rate of the process is demand-constrained. This means the shop has the capacity to handle the current demand without operating beyond its limits.
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Please explain the answer and real answers only. Find the y=mx+b
Answers
Answer:
-2
Step-by-step explanation:
Given equation
x - 2y = 4
2y = x - 4
y = ( x - 4 ) / 2
y = x/2 - 4 /2
y = x/2 - 2
Comparing with y = mx + b
y-intercept (b) = - 2
Hope it will help :)❤
Work out the ratio of AREA of Rectangle A to Rectangle B in the simplest form.
Multiple choice :
A.) 5 : 3
B.) 3 : 4
C.) 4 : 9
D.) 4 : 11
Answers
Answer:
C.) 4:9
Step-by-step explanation:
\(10*16=160\\24*15=360\\160:360=4:9\)
Answer:
C
Step-by-step explanation:
Given ratio of sides = a : b , then
ratio of areas = a² : b²
Here
ratio of sides = 16 : 24 = 2 : 3 , then
ratio of area = 2² : 3² = 4 : 9 → C
For the function {(0,1), (1,-3), (2,-4), (-4,1)}, what is the domain and range?
D: {1, -3, -4,}, R: {0, 1, 2, -4}
D:{0, 1, 2, -4}, R:{1, -3, -4}
D:{0, 1, 2, 3, 4}, R:{1, -3, -4}
Answers
I need help asap please!!
Answers
9•3=27
5-2=3
27/3=
9
5-2=3, so the answer is 3/3 which equals 1
The answer is 1
Lawrence bought his condominium for
$100,900. During the past 2 years, its
value increased 8%. What is the current
value of Lawrence's condominium?
Answers
Answer: $108,972
Step-by-step explanation:
To find the current value of Lawrence's condominium, we need to calculate the 8% increase in value over the past 2 years.
First, find the increase in value:
$100,900 * 0.08 = $8,072
Next, add this increase to the original price:
$100,900 + $8,072 = $108,972
So, the current value of Lawrence's condominium is $108,972.
If g(x)=2x+3 is a function,then find the unknown term in the following ordered pairs.
i.(a,7)
ii.(b,-1)
iii.(3,m)
plz explain.thanks for help!
Answers
Answer:
a=2, b = 1, m=9
Step-by-step explanation:
i. 7 = 2a+3 -----> 4=2a---------> a=2
ii. -1 = 2b-3 -------> 2 = 2b ------> b = 1
iii. 2(3)+3 = m -------> 6+3 = m -------> m=9
Hope this helps!!! :D
Which expression is equivalent to 11 - (-3 5/8)
Answers
Answer:
14.63
the number is rounded up it was origannaly 14.625
Can you make a Triangle with a 2 inch side, 4 inch side and 5 inch side? Why or why not? Help please
Answers
Answer:
Yes, 2+4=6 6 > 5
Explanation:
For three line segments to be able to form any triangle you must be able to take any two sides, add their length and this sum be greater than the remaining side.
Answer:
4
Step-by-step explanation:
Bacteria colonies can increase by 45% every week. If
you start with 200 bacteria microorganisms, how
large would the colony be after 35 days?
Lastly, solve and round to the nearest whole number.
Future Amount = 200(1+0.45)5
Future Amount = [?] microorganisms
Enter
Answers
r = 45% = 45 / 100 = 0.45
t = 3517 = 5
Substituting,
Future amount = (200) (1 + 0.45)^5
=1281.95
Can someone help only answer if you know and scam links are getting reported
Answers
Answer:
12 cubic centimeter blocks are in the bottom layer
Find the area of this circle
I don’t understand this
Answers
Answer:
75 in²
Step-by-step explanation:
A = πr² where radius is r = 5 in,
so,
πr²
=3×5²
=3×25 = 75 in²
Answered by GAUTHMATH
Betsy's high school is putting on a production of a play as a fundraiser for the school's music programs. A local bank has agreed to allow the school to use a line of credit from which they can withdraw money to pay for the play. Then, any deposits they make at the bank will be applied to the negative balance of the credit account. The play cost $3,200.00 to produce, and they intend to sell tickets for $10 each. After the play, Betsy will take the ticket proceeds and deposit them with the bank. If 1,007 people attend the play's opening night, what will the balance of the bank account be?
Answers
Answer:
Hey there!
If 1007 people attend, they will make a profit of 10070 dollars.
The play costed 3200 dollars to produce, so we have -3200+10070=7500 dollars as the final balance of the bank account.
Let me know if this helps :)
Answer:
Step-by-step explanation:
the correct answer is 6,870 it was d for me it might be different :)
-
It is currently 0°C outside. The temperature is dropping 2.5°C every hour. Identify an inequality that represents the number of hours that must pass for the temperature to drop below −20°C.
Answers
Answer:
-2.5x < -20
Step-by-step explanation:
x represents the number of hours that must pass for the temperature to drop below −20°C.
If QP bisects ZDQL, m/DQP = 5x - 7, and m/PQL = 11 + 2x, determine
the measure of ZDQL.
m₂DQL =
Answers
When QP bisects DQL, then the angles DQP and angle PQL is 23°.
Given that,
In the picture we can see the diagram,
The QL line is there and the QD line.
QP line bisect the angles DQL
The angle DQP is 5x-7
The angle PQL is 11+2x
We have to find the x value and the angles DQP and PQL.
We know,
From the bisection we can say the angle are equal to each other
The angle DQP=The angle PQL
5x-7=11+2x
5x-2x=11+7
3x=18
x=18/3
x=6
Substitute x value in angles DQP and angle PQL.
The angle DQP=5x-7=5(6)-7=30-7=23°
The angle PQL=11+2x=11+2(6)=11+12=23°.
Therefore, the angles DQP and angle PQL is 23°.
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Select the correct answer.
What are the solutions to this equation?
3
2x-5
=x
Answers
Answer:
3(2x-5)=x multiply the bracket by 3
6x-15=x collect like terms (x)
-15=x-6x
-15=-5x then divide both side by -5
-15=-5x
-5 -5
3=x or x=3
Step-by-step explanation:
Consider the critical value x=4 obtained from a completely continuous function f'. We find that f'(0)=−2 and f′(5)=6. What can we say about the critical value? Select all that apply.
a. There is a local maximum at x=4 b. The derivative is zero at x=4. c. That is, f′(4)=0 There is a local minimum at x=4
d. x=4 does not correspond to any local extrema
e. No conclusion can be made about extrema
Answers
Based on the given information, we can make the following conclusions about the critical value x = 4:
b. The derivative is zero at x = 4. (f'(4) = 0)
d. x = 4 does not correspond to any local extrema. (No information is given about the sign change of the derivative around x = 4, so we cannot determine if it is a local maximum or minimum.)
Therefore, the correct answers are b The derivative is zero at x = 4. (f'(4) = 0). The derivative is zero at x = 4 and d. x = 4 does not correspond to any local extrema.
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demand for sodas is normally distributed. the mean of demand is 410 sodas per day and the standard deviation of demand is 37 sodas per day. What is the probability of daily demand being less than 495 sodas?
Answers
The probability of daily demand being less than 495 sodas is approximately 0.9893 or 98.93%.
To find the probability of daily demand being less than 495 sodas, given that the mean of demand is 410 sodas per day and the standard deviation of demand is 37 sodas per day, follow these steps:
1. Convert the demand value (495 sodas) to a z-score:
z = (X - μ) / σ
z = (495 - 410) / 37
z ≈ 2.30
2. Use a z-table or a calculator with a normal distribution function to find the probability corresponding to the z-score:
P(Z < 2.30) ≈ 0.9893
Thus, the probability of daily demand being less than 495 sodas is approximately 0.9893 or 98.93%.
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