The thrust of the jet engine is 59804 N and the delivered power is 1.388 MW.
What is thrust?Thrust is defined as the amount of effort required to move an airplane through air that is resisting its passage called drag. Newton's Second and Third Laws could be used to quantitatively explain the reaction force of thrust.
Given
Speed = 232 m/s
Air intake =117 kg/s
Fuel burn rate = 4.8 kg/s
Speed of exhaust gas = 723 m/s
Rate of mass change = 117 kg/s + 4.8 kg/s
= 121.8 kg/s
Thrust T = 121.8 x 723 - 121.8 x 232
Thrust T = 88061.4 - 28257.6
Thrust T = 59804 N
Delivery power = 232 x 59804
Delivery power = 1.388 MW
Thus, the thrust of the jet engine is 59804 N and the delivered power is 1.388 MW.
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If a ball is given a push so that it has an initial velocity of 6 m/s down a certain inclined plane, then the distance it has rolled after t seconds is given by the following equation s(t) = 6t + 5t2 (a) Find the velocity after 2 seconds. m/s (b) How long does it take for the velocity to reach 40 m/s? (Round your answer to two decimal places.)
The velocity after 2 seconds is 26 m/s. It takes 11.50 seconds to reach a velocity of 40m/s.
Given the equation s(t) = 6t + 5t²
Let's find the velocity after 2 seconds.
(a) Velocity = (ds)/(dt)
Differentiating s(t) with respect to t, we get; ds(t) / dt = 6 + 10t
At t = 2,ds(t) / dt = 6 + 10t = 6 + 10(2) = 26m/s
Therefore, the velocity after 2 seconds is 26 m/s.
(b) We are to find how long it takes for the velocity to reach 40m/s. We know that the initial velocity of the ball, u = 6m/s. Acceleration = gsinθ = 9.81 x sin (angle of inclination) = 9.81 x 0.3 = 2.943 m/s²From the first equation of motion, v = u + at
We know v = 40m/s, u = 6m/s, a = 2.943m/s² and t is what we are to find, hence the equation becomes;40 = 6 + 2.943(t)t = (40 - 6) / 2.943t = 11.50s
Therefore, it takes 11.50 seconds to reach a velocity of 40m/s.
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An empty beaker is placed on a top-pan balance. Some water is now poured into the beaker.What is the weight of the water? A. 0.044 kg B. 0.168 kg C. 0.0044N D. 0.44N
Answer:
A. 0.044 kg
Explanation:
We need to subtract the sum of (beaker+water - empty beaker) which is 0.106 kg - 0.062 kg = 0.044 kg. The answer will not be written in Newton because this unit is used for force only and in this question w have to find the weight.
Hope it is enough.
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What are the four layers of the earth
Answer:
earth's crust
meatle
outercore
innercore
Answer:
the crust
the mantle core
the outer core
the inner core
Units of Planck's constant are {{c1::J s}}
The units of Planck's constant are Joule seconds (J*s).
Planck's constant is a fundamental physical constant that plays a crucial role in quantum mechanics. It relates the energy of a photon to its frequency through the equation E = hf, where E is the energy, h is Planck's constant, and f is the frequency. The unit of energy is Joules (J), and the unit of frequency is Hertz (Hz), so the unit of Planck's constant is J*s.
The significance of Planck's constant lies in its ability to bridge the gap between classical physics and quantum mechanics. It helps explain phenomena such as wave-particle duality, where particles can behave as waves and vice versa. Additionally, it is used in calculations related to atomic and subatomic particles, including the energy levels of electrons in atoms and the behavior of photons in lasers.
Overall, the units of Planck's constant demonstrate its importance as a fundamental constant in the field of quantum mechanics and its role in bridging the gap between classical physics and the mysterious realm of the subatomic world.
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A force of 20N is used to accelerate a 250g mass. What is it’s acceleration
F = 20 N
m = 250 g = 0.25 Kg
a = ?
SolutionUsing Newton's 2nd Law
F = maa = F/m
a = 20/0.25
a = 80 m/s²
The acceleration of an object with a mass of 250 grams or 0.250 kg and force applied of 20N is 80m/s².
What is Acceleration?Acceleration is the rate of change of velocity of an object. Acceleration means the speed of the object is changing, but not always. When an object moves in a circular path at a constant speed rather than variable, it is still accelerating, because the direction of its velocity is changing. It is a vector quantity as it has both the magnitude and direction. The SI unit of acceleration is meter per second (m/s²).
According to the formula,
f = m × a
f = force,
m = mass of the body,
a = acceleration of the body
f = 20N
m = 250 grams = 0.250kg (1kg = 1000grams)
f = m × a
a = f/ m
a = 20N/ 0.250kg
a = 80m/s²
The acceleration of the body is 80m/s².
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A 0. 36-kg block rests on a frictionless level surface and is attached to a horizontally aligned spring with a spring constant of 48 n/m. The block is initially displaced 5 cm from the equilibrium point and then released to set up a simple harmonic motion. A frictional force of 0. 3 n exists between the block and surface. What is the speed of the block when it passes through the equilibrium point after being released from the 5-cm displacement point?.
The block moves at a speed of 40 m/s2 when it reaches the equilibrium point after being freed from the 5-cm displacement point.
What time of year is spring?Indian culture considers the months of March and April to be the start of spring, with an average high temperature of about 32 °C. Ugadi, the springtime celebration of some Indians, is notably popular in the state of Karnataka.
What makes springs crucial to physics?Springs play a crucial role in many complex physical systems because they provide as straightforward models for them. As you continue studying physics, you will see SHM repeatedly as it describes how things that behave like springs behave. the spring constant being denoted by k.
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30. A generation is about one-third of a lifetime. Approximately how many generations have passed since the year 0 AD?
Answer:84 generations
Explanation:
A generation is about one-third of a lifetime. Approximately how many generations have passed since the year 0 AD? Approximately 84 generation.
Energy stores in food would be considered what
Answer:
Energy stored in food is consider as carbohydrate,protein,fats,etc.
how will the pressure of a real gas compare to the pressure of an ideal gas?select the correct answer below:the pressure of a real gas is generally greater than the pressure of an ideal gas.the pressure of a real gas is generally less than the pressure of an ideal gas.the pressure of a real gas is generally equal to the pressure of an ideal gas.the relationship between the pressure of a real gas and an ideal gas will depend on the conditions and identity of the gas.
The pressure of a real gas will generally be different from the pressure of an ideal gas, and the relationship between the two will depend on the conditions and identity of the gas. Therefore, the correct answer is (d)
An ideal gas is a theoretical gas that obeys the ideal gas law, which is based on the assumptions that the gas particles have no volume and do not interact with each other. In reality, gas particles have a finite volume and interact with each other through intermolecular forces, which can affect the pressure of the gas.
At low pressures and high temperatures, most gases behave like ideal gases, and the pressure of a real gas is very close to the pressure of an ideal gas.
However, at high pressures and low temperatures, the volume of the gas particles becomes significant, and the intermolecular forces become important, causing the pressure of a real gas to deviate significantly from the pressure of an ideal gas.
Hence, (d) is the right option.
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water makes up ______ of the volume of saliva and is its primary ingredient.
Water makes up approximately 99% of the volume of saliva and is its primary ingredient.
Saliva is a clear, watery fluid that is secreted by the salivary glands located in the mouth. It plays an important role in the digestion process by moistening food, making it easier to swallow, and breaking down starches and fats.
In addition to water, saliva also contains enzymes, electrolytes, mucus, and antibacterial compounds that help protect the teeth and gums from bacteria and infection.
The amount and consistency of saliva produced can vary depending on factors such as age, medication use, and certain medical conditions. A dry mouth, or xerostomia, can occur when there is a decrease in the production of saliva, which can lead to problems with speech, swallowing, and dental health.
Therefore, it is important to maintain proper hydration and oral hygiene to support the production of saliva and ensure good overall health.
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Newton’s second law of motion is also known as law of _____
Consider a signal x[n] having the corresponding Fourier transform X(e jw
). What would be the Fourier transform of the signal y[n]=2x[n+3] Select one: X(e jw
)e j3w
2X(e jw
)e j3w
2X(e jw
)e −j3w
3X(e jw
)e j2w
−2X(e jw
)e −j3w
The Fourier transform of the signal y[n]=2x[n+3] is 2X(\(e^(^j^w^)\))\(e^(^j^3^w^)\).
When we have a signal y[n] that is obtained by scaling and shifting another signal x[n], the Fourier transform of y[n] can be determined using the properties of the Fourier transform.
In this case, the signal y[n] is obtained by scaling x[n] by a factor of 2 and shifting it by 3 units to the left (n+3).
To find the Fourier transform of y[n], we can use the time-shifting property of the Fourier transform. According to this property, if x[n] has a Fourier transform X(\(e^(^j^w^)\)), then x[n-n0] corresponds to X(\(e^(^j^w^)\)) multiplied by \(e^(^-^j^w^n^0^)\).
Applying this property to the given signal y[n]=2x[n+3], we can see that y[n] is obtained by shifting x[n] by 3 units to the left. Therefore, the Fourier transform of y[n] will be X(\(e^(^j^w^)\)) multiplied by \(e^(^j^3^w^)\), as the shift of 3 units to the left results in \(e^(^j^3^w^)\).
Finally, since y[n] is also scaled by a factor of 2, the Fourier transform of y[n] will be 2X(\(e^(^j^w^)\)) multiplied by \(e^(^j^3^w^)\), giving us the main answer: 2X(\(e^(^j^w^)\))\(e^(^j^3^w^)\).
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Select an item that is common in our society that you believe is elastic and, using two determinants of elasticity (pages 133-134), briefly explain why you believe this product is elastic.
Select an item that is common in our society that you believe is inelastic and, using two determinants of elasticity (pages 133-134), briefly explain why you believe this product is inelastic. Expectations are a minimum of one paragraph (4 to 5 sentences) for each question in the initial post.
There are no immediate substitutes for gasoline as public transportation is often limited and walking, biking, or taking a cab is not always feasible. Therefore, people may continue to purchase gasoline despite an increase in price.
One item that is common in our society that I believe is elastic is fast food. Elasticity is the degree to which changes in price affect demand for a good or service.
Fast food is elastic because it has many substitutes such as restaurants, home-cooked meals, and even other fast-food chains. Fast food is also highly responsive to price changes, which means that a small change in price can cause a large change in demand.
For example, a $1 price increase for a burger meal at a fast-food chain might cause many people to switch to a competitor with a cheaper price. Thus, fast food is an elastic product in our society.One item that is common in our society that I believe is inelastic is gasoline.
Gasoline is an inelastic product because it has few substitutes and people need it for transportation. If the price of gasoline increases, people may continue to purchase it even if it means spending more money because there are few alternative options.
Additionally, there are no immediate substitutes for gasoline as public transportation is often limited and walking, biking, or taking a cab is not always feasible.
Therefore, people may continue to purchase gasoline despite an increase in price.
For example, if the price of gasoline increases by $1, a consumer will still purchase gasoline because they require it to get to work or school. Thus, gasoline is an inelastic product in our society.
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One item in our society that I believe is elastic is the price of gasoline because of various alternatives to gasoline and the proportion of income spent. An item in our society that I believe is inelastic is medical treatment because of the necessity of medical treatment and lack of substitutes.
Firstly, the availability of substitutes contributes to the elasticity of gasoline. In our society, there are various alternatives to gasoline, such as electric vehicles or public transportation. When the price of gasoline increases, consumers have the option to switch to these substitutes, reducing their demand for gasoline. Conversely, when the price of gasoline decreases, consumers may choose to drive more or purchase larger vehicles, increasing their demand for gasoline. This flexibility in consumer choices demonstrates the elasticity of gasoline.
Secondly, the proportion of income spent on the product also influences the elasticity of gasoline. For many individuals, the cost of gasoline represents a significant portion of their overall budget. When the price of gasoline rises, consumers may have to make adjustments to their spending habits or seek alternative means of transportation to cope with the higher expenses. Conversely, when the price of gasoline decreases, consumers may have more disposable income to spend on other goods and services. This sensitivity to price changes further supports the elasticity of gasoline.
On the other hand, an item in our society that I believe is inelastic is medical treatment. Two determinants of elasticity that contribute to this belief are the necessity of the product and the lack of substitutes.
Firstly, the necessity of medical treatment makes it an inelastic product. When individuals require medical treatment, they often have no choice but to seek the necessary healthcare services regardless of the price. This is especially true for life-saving procedures or medications. The demand for medical treatment is driven by the urgency and importance of preserving one's health, which leads to a less responsive consumer behavior to price changes.
Secondly, the lack of substitutes also contributes to the inelasticity of medical treatment. In many cases, there are limited alternatives or substitutes available for specific medical treatments. For example, if a person requires a specific surgery or medication to treat a condition, they cannot easily switch to a different treatment option to lower their expenses. The lack of viable substitutes reduces consumer choice and makes the demand for medical treatment less responsive to changes in price.
In summary, the price of gasoline is elastic due to the availability of substitutes and the proportion of income spent on the product. On the other hand, medical treatment is inelastic due to its necessity and the lack of substitutes. These determinants of elasticity highlight the different levels of responsiveness to price changes in these two common items in our society.
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The conversion of sugar to energy in the presence of oxygen is
A.
respiration
B.
protein synthesis
C.
binary fission
D.
photosynthesis
Answer:
A. respiration.
Explanation:
Cellular respiration can be defined as a series of metabolic reactions that typically occur in cells so as to produce energy in the form of adenosine triphosphate (ATP). During cellular respiration, high energy intermediates are created that can then be oxidized to make adenosine triphosphate (ATP). Therefore, the intermediary products are produced at the glycolysis and citric acid cycle stage.
Additionally, mitochondria provides all the energy required in the cell by transforming energy forms through series of chemical reactions; breaking down of glucose into Adenosine Triphosphate (ATP) used for providing energy for cellular activities in the body of living organisms.
Basically, oxygen goes into the body of a living organism such as plants, humans and animals when they breathe while glucose is absorbed by the body when they eat.
Hence, the conversion of sugar to energy in the presence of oxygen is respiration.
If a plane is traveling at a velocity of 100 km/hr East, and if the wind velocity is 25 km/hr to the East, then what is the velocity of the plane relative to an
observer on the ground below?
100 km/hr East
75 km/hr West
75 km/hr East
125 km/hr East
Answer:
75 west
Explanation:
I think not sure lucky guess
Suppose you graphS i n open parentheses theta subscript 1 close parenthesesVs.S i n open parentheses theta subscript 2 close parenthesesand get a slope m = 0.413. If the second material is air (n2 = 1.0003), use equation 2 in the manual to calculate n1.
n1 = 1
n1 = 2.42
n1 = 1.46
n1 = 1.47
n1 = 1.49
n1 = 0.413
The equation mentioned in the manual is:
m = (n2/n1) * (cos(theta1)/cos(theta2))
n1 = 2.42
What is the value of n1 if the slope obtained from the graph of sin(theta1) vs. sin(theta2) for two materials (one of which is air with n2 = 1.0003) is m = 0.413, according to equation 2 in the manual?The equation mentioned in the manual is:
m = (n2/n1) * (cos(theta1)/cos(theta2))
where m is the slope obtained from the graph of sin(theta1) vs. sin(theta2), n1 and n2 are the refractive indices of the two materials, and theta1 and theta2 are the angles of incidence and refraction, respectively.
In this problem, we have n2 = 1.0003 (since the second material is air). We also know that sin(theta1) = sin(theta2), since the graph is of sin(theta1) vs. sin(theta2). Therefore, cos(theta1) = sqrt(1-sin^2(theta1)) = sqrt(1-sin^2(theta2)) = cos(theta2).
Substituting these values into the equation above, we get:
0.413 = (1.0003/n1) * 1
Simplifying this expression, we get:
n1 = 1.0003/0.413 = 2.42
Therefore, the correct answer is n1 = 2.42.
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Shown here is a portion of the activity table. Based
on the table, which activity burns the least amount
of calories per hour?
doing aerobics
O jogging
walking
Answer: The answer is walking. Hope it helps anybody :)
Explanation: The answer to the second question is glycogen and lipids.
Answer:
Walking
Explanation:
Took test
The angular speed of a rotating platform changes from ω0 = 4.4 rad/s to ω = 8.8 rad/s at a constant rate as the platform moves through an angle Δθ = 5.5 radians. The platform has a radius of R = 34 cm.
A) Calculate the angular acceleration of the platform α in rad/s2.
B) Calculate the tangential acceleration at in m/s2 of a point on the surface of the platform at the outer edge.
C) Calculate the final centripetal acceleration ac, in m/s2, of a point at the outer edge of the platform.
MAIN ANSWER in 30 WORDS:
A) α = 8.8 rad/s^2; B) at = 118.8 m/s^2; C) ac = 413.52 m/s^2.
EXPLANATION PART IN 120 WORDS:
A) Angular acceleration α can be calculated using the formula α = (ω - ω0)/Δθ. Substituting values, we get α = (8.8 - 4.4)/5.5 = 0.8 rad/s^2.
B) Tangential acceleration at can be calculated using the formula at = Rα, where R is the radius of the platform. Substituting values, we get at = 34 × 0.8 = 27.2 m/s^2.
C) Final centripetal acceleration ac can be calculated using the formula ac = Rω^2, where ω is the final angular velocity. Substituting values, we get ac = 34 × 8.8^2 = 413.52 m/s^2.
Therefore, the angular acceleration is 0.8 rad/s^2, the tangential acceleration at the outer edge of the platform is 27.2 m/s^2, and the final centripetal acceleration at the outer edge of the platform is 413.52 m/s^2.
The angular acceleration of the platform is 0.8 rad/s^2, the tangential acceleration at the outer edge of the platform is 27.2 m/s^2, and the final centripetal acceleration at the outer edge of the platform is 2617.6 m/s^2.
A) The angular acceleration α of the platform can be calculated using the formula: α = (ω^2 - ω0^2) / (2Δθ). Plugging in the values, we get α = (8.8^2 - 4.4^2) / (2 * 5.5) = 44/11 rad/s².
B) The tangential acceleration at of a point on the outer edge can be calculated using the formula: at = α * R. Converting R to meters, we get R = 0.34 m. Thus, at = (44/11) * 0.34 = 1.36 m/s².
C) The final centripetal acceleration ac can be calculated using the formula: ac = ω^2 * R. Plugging in the values, we get ac = 8.8^2 * 0.34 = 26.424 m/s².
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A turntable slows from an initial rate of 28.0 rad/s at a rate of 0.580 rad/s2. The turntable is a disk with a diameter of 40.0 cm and mass of 2.00 kg: The slowing of the turntable is due to a frictional force exerted 1.00 cm from the axis of rotation (a) Determine the magnitude of the tangential acceleration of a point on the edge of the turntable: m/s2 Determine the time it takes the turntable to come to rest_ (c) Determine the number of revolutions the turntable makes before stopping: revolutions (d) Determine the magnitude of the torque exerted on the turntable Nm (e) Determine the magnitude of the frictional force. Determine the magnitude of the initial angular momentum of the turntable_ kg m?/s
(a) The magnitude of the tangential acceleration of a point on the edge of the turntable is 0.290 m/s².
(b) The time it takes the turntable to come to rest is 48.3 s.
(c) The number of revolutions the turntable makes before stopping is 4.79 revolutions.
(d) The magnitude of the torque exerted on the turntable is 0.116 Nm.
(e) The magnitude of the frictional force is 0.116 N.
(f) The magnitude of the initial angular momentum of the turntable is 0.056 kg m²/s.
(a) The tangential acceleration can be calculated using the formula a = α × r, where α is the angular acceleration and r is the radius of the turntable. Given α = -0.580 rad/s² and r = 0.20 m (half of the diameter), we find a = 0.290 m/s².
(b) The time it takes for the turntable to come to rest can be determined using the equation vf = vi + at, where vf is the final velocity (zero in this case), vi is the initial velocity (28.0 rad/s), a is the acceleration (-0.580 rad/s²), and t is the time. Rearranging the equation, we have t = (vf - vi) / a = -28.0 rad/s / (-0.580 rad/s²) = 48.3 s.
(c) The number of revolutions the turntable makes before stopping can be found using the equation θ = ωi × t + 0.5 × α × t², where θ is the angle in radians, ωi is the initial angular velocity, t is the time, and α is the angular acceleration. Since ωi = 28.0 rad/s, α = -0.580 rad/s², and t = 48.3 s, we can calculate θ = 4.79 revolutions.
(d) The magnitude of the torque exerted on the turntable can be determined using the equation τ = I × α, where τ is the torque, I is the moment of inertia, and α is the angular acceleration. The moment of inertia for a disk rotating about its axis is given by I = (1/2) × m × r², where m is the mass of the disk and r is its radius. Substituting the given values, we find τ = 0.116 Nm.
(e) The magnitude of the frictional force can be calculated using the equation f = m × a, where f is the force, m is the mass, and a is the acceleration. Substituting the given values, we find f = 0.116 N.
(f) The magnitude of the initial angular momentum of the turntable can be calculated using the equation L = I × ω, where L is the angular momentum, I is the moment of inertia, and ω is the angular velocity. Substituting the given values, we find L = 0.056 kg m²/s.
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Heat is the transfer of thermal energy.
O A. True
B. False
Answer:
True
Explanation:
Heat is when thermal energy is transferred from one object to another. Thermal energy produces heat when it is moving from one object to another, so when it does, thermal energy gets transferred. So, the answer to your question is true because thermal energy can travel through conduction, convection or radiation.
A hockey puck with mass 170 g is attached to a rope of length 65.0 cm and swung in a horizontal circle against the ice at a rate of 53.0 rpm. Assuming the ice is frictionless, what is the tension in the rope?
This question involves the concepts of tension force and centripetal force.
The tension force in the rope is "3.4 N".
In this scenario, the centripetal force shall be acting as the tension force of the rope. Because in order for the puck to move in a circular path, the tension force in the rope must be equal to the centripetal force.
\(Tension\ Force = Centripetal\ Force\\F = \frac{mv^2}{r}\)
where,
F = tension force = ?
m = mass of puck = 170 g = 0.17 kg
r = radius of path = length of rope = 65 cm = 0.65 m
v = linear speed of puck = r(angular speed) = (0.65 m)(53 rpm)\((\frac{2\pi\ rad}{1\ rev})(\frac{1\ min}{60\ s})\)
v = 3.61 m/s
Therefore,
\(F = \frac{(0.17\ kg)(3.61\ m/s)^2}{0.65\ m}\)
F = 3.4 N
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The attached picture shows the centripetal force.
Which muscle is the main muscle of mastication?
Answer: Masseter muscle
Explanation:
The masseter muscle is the most powerful muscle of mastication. It is quadrangular in shape and has two parts: deep and superficial. The entirety of the muscle lies superficially to the pterygoids and temporalis, covering them.
Which one of the following conditions is linked to poverty, insufficient food intake, poor food quality unsanitary living conditions, and improper feeding of infants and young children?
Obesity
Heart disease
Cancer
Protein-energy malnutrition
Protein-energy malnutrition is the condition linked to poverty, insufficient food intake, poor food quality, unsanitary living conditions, and improper feeding of infants and young children. The correct option is 4.
Protein-energy malnutrition (PEM) is a type of malnutrition that occurs when there is a deficiency in both protein and energy (calories) intake. It is often associated with impoverished and disadvantaged populations who lack access to an adequate and balanced diet. PEM can lead to severe health consequences, including stunted growth, weakened immune system, and increased susceptibility to infections and diseases.
Efforts to combat PEM include improving food security, promoting better nutrition practices, and enhancing access to essential nutrients through supplementation and fortification of food. Addressing poverty, improving living conditions, and ensuring proper healthcare and education are also crucial in preventing and treating protein-energy malnutrition in vulnerable populations.
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An Eskimo pushes a loaded sled with a mass of 300kg for a distance of 25m over the frictionless surface of hard packed snow. He exerts a constant 170 N force as he does so. If the sled starts from rest, what is its acceleration in m/s^2
The acceleration of the sled of mass 300 kg is 0.57 m/s².
What is acceleration?Acceleration is the rate of change of the velocity of a body.
To calculate the acceleration of the sled, we use the formula below.
Formula:
a = F/m............................. Equation 1Where:
a = AcccelerationF = Forcem = MassFrom the question,
Given:
F = 170 Nm = 300 kgSubstitute these values into equation 1
a = 170/300a = 0.57 m/s²Hence, the acceleration of the sled is 0.57 m/s².
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What is the kinetic energy of a 3-kg ball that is rolling at 2 meters per second?
Answer: 6J
Explanation:
Formula calculates Kinetic energy is
K= 1/2mv^2
So just need to put the number in the equation and you will get the answer.
The location of a planet relative to the Sun has a lot to do with its _____; whether it is one of the inner terrestrial planets or outer gas giants.
Answer:
Composition.
Explanation:
the inner planets tend to be made up of more solid materials such as iron, while outer planets are made up of primarily gas and ice
A person with a mass of 60.0 kg is traveling at 18 m/s.
How much kinetic energy does this person have?
Kinetic energy
K = 1 /2 m v ²
= 1 /2 × 60 × 18² = 9720J
Operators must have unobstructed access to a ladder for escape from a trench within what distance?
a) 15 feet
b) 20 feet
c) 25 feet
d) 30 feet
Operators must have unobstructed access to a ladder for escape from a trench within a distance of 25 feet.
According to OSHA regulations, operators must have unobstructed access to a ladder for escape from a trench within 25 feet. So, the correct answer is c 25 feet.
According to OSHA Occupational Safety and Health Administration, employers must provide ladders, steps, ramps, or other safe means of egress for workers working in trench excavations 4 feet 1.22 meters or deeper1. The means of egress must be located so as not to require workers to travel more than 25 feet 7.62 meters laterally within the trench1. Therefore, the answer is c 25 feet. Operators must have unobstructed access to a ladder for escape from a trench within 25 feet. So, the correct answer is c 25 feet
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Calculate the acceleration of a train of mass 30 000 kg when driven by a force of 15000 N.
Answer:
Explanation:
F = ma, so filling in:
15000 = 30000a and
a = .50 m/s/s
The acceleration of a train is 0.50 \(m/s^{2}\).
What is acceleration?Acceleration is the rate of change of the velocity of an object with respect to time.
F = ma
a = F/m
a = 15000/30000
a = 0.50 \(m/s^{2}\)
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40 g of which substance is saturated in 100 g of water at a temperature of 50°C?
A
KCI
B
Nacl
C
KNO3
D
NH4Cl
please help , its due soon