(0) Calculate the momentum of the vehicle when it moves at the maximum speed of 90 km/h with load of 3000 kg
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Klyde has a larger linear (tangential) velocity than Bonnie on the merry-go-round.

The linear velocity of an object moving in a circular path is given by the formula v = rω, where v is the linear velocity, r is the distance from the center of the circle, and ω is the angular velocity. In this scenario, Bonnie sits on the outer rim of the merry-go-round, while Klyde sits midway between the center and the rim. Since Bonnie is farther from the center than Klyde, her distance (r) is larger. Since the merry-go-round makes one revolution every 2 seconds, the angular velocity (ω) is the same for both Bonnie and Klyde. As a result, Klyde, being closer to the center, has a smaller distance (r) but the same angular velocity, resulting in a larger linear velocity (v) compared to Bonnie.



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Answer:

There is a right angle and it has three sides.

Explanation:

There are two 45 degree angles and since a triangles sides ALWAYS add up to 180 we know the the other side has to be 90 degrees because 45+45+90=180. And we know that every triangle has three sides because "tri" means three.

Newton's third law states that any action will have a(n) equal and opposite reaction.

The correct option is A.

Sour receptors help in the detection of the presence of acids in substances, whereas salt receptors help in the detection of sodium in substances.

A sour type of taste is considered as a quality of primary task that makes an innate rejection type of response in humans as well as in many other animals. Generally, Acidic stimuli are certain unique sources of a sour taste as whenever a  rejection response might serve a discouragement of ingestion of foods which is spoiled by microorganisms that produce acids. The mechanisms by which an acid excites receptor cells of taste (TRCs) are actually complicated by the variability of wide species and are within species that are apparently different kinds of mechanisms for the case of strong and weak acids in substances.

The presence of epithelial sodium channels mediates the mechanism of salt taste. Usually, these receptors are open, and whenever foods are ingested with a high concentration of salt, sodium starts to flow into the cell which causes depolarization. This change occuring in the membrane potential then opens to voltage-gated sodium as well as calcium channels. The calcium influx is in an increased state that causes releasing of serotonin which is filled by vesicles. The serotonin aids in the acting of afferent taste as by axon which causes depolarization and action potentials.

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Answer:

Workdone = 30Nm

Explanation:

Given the following data;

Force = 10N

Distance = 3m

To find the workdone;

Workdone = force * distance

Substituting into the equation, we have

Workdone = 10 * 3

Workdone = 30Nm.

Therefore, the work involved in moving the box is 30 Newton-meter.

Answer:

6. Paula is correct. Think about buildings, buildings are constantly pushed by different forces like wind or gravity. The buildings aren’t moving but this doesn’t mean that they aren’t under force

Explanation:

Answer:

Hello this is allina from brainly. I'll be helping you today. Use the formula, v=gt to find the velocity.

For example, the velocity after one second would be g * t = 10 m/s^2 * 1, which would be 10 m/s.

So, just put the time into the equation:

ii. 20 m/s

iii. 30 m/s

iv. 50 m/s

The formula d = 1/2gt^2 is for finding the distance it has fallen in free fall.

SO plug in the value for t into the equation.

i. 5 m

ii. 20 m

iii. 45 m/s

iv. 125 m/s

Use the previous formula (v = gt) to find the time it has fallen:

v = gt

30 m/s = 10 m/s^2 * t

t = 3 s

So it has fallen for 3 seconds.

Use the 3 seconds to find the distance it has fallen in free fall:

d = 1/2gt^2

d = 1/2 * 10 m/s^2 * 3^2 s

d = 45 m

Explanation:

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The magnitude of B⃗ ×A⃗ is equal to the product of the magnitudes of vectors A⃗ and B⃗.

|B⃗ ×A⃗ | = |( |A||B|, 0, 0 )| is the direction of A⃗ ×B⃗.

|B⃗ ×A⃗ | = √(|A||B|)² + 0² + 0² is the direction of B⃗ ×A⃗.

|B⃗ ×A⃗ | = √(|A|²|B|²) is the magnitude of A⃗ ×B⃗.

|B⃗ ×A⃗ | = |A||B| is the magnitude of B⃗ ×A⃗.

To find the magnitude of B⃗ ×A⃗, we first need to determine the cross product of B⃗ and A⃗. The cross product of two vectors A⃗ and B⃗ is another vector C⃗ that is perpendicular to both A⃗ and B⃗. The direction of the cross product is determined by the right-hand rule, which states that if you curl the fingers of your right hand from A⃗ to B⃗, then your thumb will point in the direction of C⃗.

Since vector A⃗ points along the negative x-axis, its components are (-|A|, 0, 0). Similarly, vector B⃗ along the positive z-axis has components (0, 0, |B|). The cross product of these two vectors is given by:

B⃗ ×A⃗ = (0, -|B|, 0) × (-|A|, 0, 0)

Using the cross product formula, we can calculate:

B⃗ ×A⃗ = (0×0 - (-|B|)×(-|A|), 0×(-|A|) - 0×0, 0×0 - 0×(-|B|))
B⃗ ×A⃗ = (|A||B|, 0, 0)

The magnitude of this vector is simply the length of the vector, which is given by:

|B⃗ ×A⃗ | = |( |A||B|, 0, 0 )|
|B⃗ ×A⃗ | = √(|A||B|)² + 0² + 0²
|B⃗ ×A⃗ | = √(|A|²|B|²)
|B⃗ ×A⃗ | = |A||B|

Therefore, the magnitude of B⃗ ×A⃗ is equal to the product of the magnitudes of vectors A⃗ and B⃗.

|B⃗ ×A⃗ | = |( |A||B|, 0, 0 )| is the direction of A⃗ ×B⃗.

|B⃗ ×A⃗ | = √(|A||B|)² + 0² + 0² is the direction of B⃗ ×A⃗.

|B⃗ ×A⃗ | = √(|A|²|B|²) is the magnitude of A⃗ ×B⃗.

|B⃗ ×A⃗ | = |A||B| is the magnitude of B⃗ ×A⃗.

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The width of the central bright fringe can be calculated as half the distance between the third-order minima is 10.5 cm

The **width of the central bright fringe** in a two-slit interference pattern can be determined using the formula:

**Width of central bright fringe** = (λ × D) / d

where λ is the wavelength of light, D is the distance between the slits and the screen, and d is the distance between the slits.

In this case, the third-order minima are 21.0 cm apart. The central bright fringe is located between these two minima. Since the bright fringes are evenly spaced, the distance between adjacent fringes is the same. Therefore, the width of the central bright fringe can be calculated as half the distance between the third-order minima:

Width of central bright fringe = 21.0 cm / 2 = 10.5 cm

However, the given answer states that the width is 4.18 cm. It seems there might be an error in the calculation or information provided. Please double-check the values and calculations to ensure accuracy.

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The correct answer is A. A water molecule entering the lake will remain in the lake for 600 years.

Residence time refers to the average amount of time that a water molecule spends in a particular body of water, such as a lake. In the case of Lake Tahoe, the residence time is approximately 600 years. This means that, on average, a water molecule that enters the lake will remain in the lake for 600 years before leaving through the outlet.

Option B is incorrect because the total volume of water in Lake Tahoe can vary due to precipitation, evaporation, and other factors.

Option C is also incorrect because the residence time of water in Lake Tahoe does not necessarily relate to the ability of the lake to sustain aquatic life.

Option D is incorrect because outflow from Lake Tahoe occurs regularly and is not limited to once every 600 years.

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The Sun has a complex magnetic field that is generated by the movement of charged particles in its outer layers, known as the convection zone. The Sun's magnetic field is dynamic and can undergo significant changes over time, with its behavior being influenced by the solar cycle.

The solar cycle is a period of approximately 11 years during which the Sun's magnetic field undergoes a complete reversal. At the beginning of the solar cycle, the magnetic field is weak and has a simple structure with a single polarity. As the cycle progresses, the magnetic field becomes more complex and stronger, with the appearance of sunspots and other features indicating the presence of magnetic activity.

During this period, the magnetic field lines become twisted and stretched, forming loops and arches that can extend far above the Sun's surface. These structures can become unstable and release energy in the form of solar flares and coronal mass ejections, which can have a significant impact on the Earth's environment and technology.

After the peak of the solar cycle, the magnetic field begins to weaken and become less complex, eventually returning to a simple, single-polarity configuration at the start of the next cycle.

Overall, the Sun's magnetic field is a complex and dynamic system that undergoes significant changes over time, with its behavior being driven by the movement of charged particles in the convection zone and influenced by the solar cycle.

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The air speed of the helicopter has the ground speed of 250 km/h is 233 km/h  

The ground speed of the helicopter = 250 km/h

The wind speed of the helicopter = 17 km/h

The air speed of the helicopter can be found using the formula,

            G = W + A
where G is the ground speed of the helicopter

           W is the wind speed of the helicopter

           A is the air speed of the helicopter

Let us rearrange the equation in order to get the airspeed,

          A = G - W

Let us substitute the known values in the above equation, we get

          A = 250 - 17

              = 233 km/h  

Therefore, the air speed of the air speed is 233 km/h

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The air temperature at the diffuser exit is approximately 79 degC.

We can use the conservation of energy equation to determine the temperature of the air at the diffuser exit, assuming ideal gas behavior. The conservation of energy equation can be written as;

(1/2) × m × v₁² + m × c × T₁ = (1/2) × m × v₂² + m × c × T₂

where m is the mass of the air, v₁ and v₂ are the velocities of the air at the inlet and outlet of the diffuser, respectively, c is the specific heat capacity of air at constant pressure, T₁ is the initial temperature of the air, and T₂ is the temperature of the air at the diffuser exit.

Since the air is slowed down to essentially zero velocity at the diffuser exit, we can assume that v₂ is zero. Thus, the conservation of energy equation becomes;

(1/2) × m × v₁² + m × c × T₁ = m × c × T₂

Simplifying and rearranging the equation, we get;

T₂ = T₁ + (v₁² / (2 × c))

We are given that the initial temperature T₁ is 37 degC and the velocity v₁ is 300 m/s. The specific heat capacity of air at constant pressure, c, is approximately 1005 J/(kg·K), and the molar mass of air, Mair, is approximately 28.97 g/mol.

Converting the velocity to SI units (m/s) and the temperature to Kelvin, we get;

T₁ = 37 + 273 = 310 K

v₁ = 300 m/s

Put these values into equation for T₂, we have;

T₂ = 310 + (300² / (2 × 1005)) = 352 K

Converting the temperature back to degrees Celsius, we get;

T₂ = 352 - 273

= 79 degC

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Answer:

4000 J

Explanation:

KE = (1/2)(m)(v^2)

KE = .5*500*(4^2)

KE = 4000 J

The ratio of kinetic energies of a gas at 200 °C and 100 °C is approximately 1.268 .

It can be determined using the equation:

K.E. = (3/2) * n * R * T

Where:

K.E. = Kinetic energy of the gas

n = Number of moles of the gas

R = Gas constant (8.314 J/(mol·K))

T = Temperature in Kelvin

To calculate the ratio of kinetic energies between 200 °C and 100 °C, we need to convert the temperatures to Kelvin.

200 °C = 200 + 273.15 = 473.15 K

100 °C = 100 + 273.15 = 373.15 K

Now, let's calculate the kinetic energy at each temperature:

K.E.(200 °C) = (3/2) * n * R * 473.15

K.E.(100 °C) = (3/2) * n * R * 373.15

To find the ratio, we divide the kinetic energy at 200 °C by the kinetic energy at 100 °C:

Ratio = K.E.(200 °C) / K.E.(100 °C)

     = [(3/2) * n * R * 473.15] / [(3/2) * n * R * 373.15]

     = 473.15 / 373.15

     ≈ 1.268

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Answer:

C. 1.50×10¹¹ m

Explanation:

First, convert the time to seconds.

8 min × (60 s/min) + 20 s = 500 s

Distance = speed × time

d = (3×10⁸ m/s) (500 s)

d = 1.50×10¹¹ m

The distance from the Sun to the Earth is 1.50 × 10¹¹. Speed is the distance travelled by an object in a particular time period. Thus, the correct option is C.

The speed of light in vacuum is commonly denoted by c. It is a universal physical constant. The speed of light (c) is exactly equal to 3.00 x 10⁸m/s (meter per second).

The speed of an object is the rate of change of position with respect to time. It is also defined as the distance covered by an object with respect to time. It can be calculated by dividing the distance travelled by an object by the time taken. It is a scalar quantity as it has only magnitude and no direction.

Speed = Distance / time

Distance = Speed × Time

Distance = 3.00 × 10⁸ × 500

Distance = 1500 × 10⁸

Distance =  1.50 × 10¹¹

Therefore, the correct option is C.

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Answer:

0 m/s²

Explanation:

Velocity is the slope of the position vs time graph.  The graph is linear, so the velocity is constant.  Since the velocity is constant, the acceleration is 0.

Answer:

The answer to your question is given below.

Explanation:

The following data were obtained from the question:

Velocity (v) = 45 m/s

Time 5 (t₅) = 5 s

Time 6 (t₆) = 6 s

Displacement at 5 s (d₅) =.?

Displacement at 6 s (d₆) =.?

1. Determination of the displacement after 5 s.

Velocity (v) = 45 m/s

Time 5 (t₅) = 5 s

Displacement at 5 s (d₆) =.?

Velocity = Displacement /Time

v = d₅ /t₅

45 = d₅ / 5

Cross multiply

d₅ = 45 × 5

d₅ = 225 m

2. Determination of the displacement after 6 s.

Velocity (v) = 45 m/s

Time 6 (t₆) = 6 s

Displacement at 6 s (d₆) =.?

Velocity = Displacement /Time

v = d₆ /t₆

45 = d₆ / 6

Cross multiply

d₆ = 45 × 6

d₆ = 270 m

Summary:

Time >>>>>> Displacement

5 >>>>>>>>> 225 m

6 >>>>>>>>> 270 m

From the calculations made above the displacement of the ball after 6 seconds is greater than the displacement after 5 seconds.

Answer:

???????????????????????

Explanation:

The x - component of the initial velocity is given as:

Ux = Vi cos theta

Ux = 100cos 60

Ux = 50m/s

When you push a pencil off your desk, the energy transformation that takes place is that potential energy transforms into kinetic energy.

The correct answer to the given question is option C.

Potential energy is the energy stored within an object because of its position or configuration.

In this scenario, the pencil has potential energy because of its elevated position on the desk. When the pencil is pushed off the desk, it begins to move, which means that it has kinetic energy. Kinetic energy is the energy of motion.

As the pencil falls off the desk, its potential energy is transformed into kinetic energy, which is the energy that results from its motion. The faster the pencil falls, the greater its kinetic energy will be because kinetic energy is directly proportional to the square of an object's velocity.

Therefore, when you push a pencil off your desk, the potential energy that it has because of its elevated position is transformed into kinetic energy as it falls towards the ground.

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Answer:

Ingles porfavor

Explanation:

Answer:

j type the question into wolfram it gives you answer plus explanation

Answer: There are not able to be electricity

Explanation: Essentially, this means that the electricity is able to pass through the birds without damaging them.

v_final / v_initial = sqrt(1.5), the magnitude of the object's momentum is changed by a factor of sqrt(1.5).

To answer your question, we will use the following formulas:

1. Kinetic energy (KE) = 0.5 * mass (m) * velocity^2 (v^2)
2. Momentum (p) = mass (m) * velocity (v)

Given that the kinetic energy of an object is increased by a factor of 1.5, we have:

1.5 * KE_initial = KE_final

Now, let's express the final velocity (v_final) in terms of initial velocity (v_initial):

KE_final = 0.5 * m * v_final^2

1.5 * (0.5 * m * v_initial^2) = 0.5 * m * v_final^2

Cancel out the common factors and solve for the ratio of final to initial velocity:

1.5 * v_initial^2 = v_final^2
v_final / v_initial = sqrt(1.5)

Now, let's find the factor by which the magnitude of its momentum changed:

p_initial = m * v_initial
p_final = m * v_final

Factor of change in momentum = p_final / p_initial = (m * v_final) / (m * v_initial) = v_final / v_initial

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Percent error and percent difference are mathematical measures used to compare experimental or measured values with theoretical or known values. While they provide information about the discrepancy between the measured and expected values, they do not directly indicate the accuracy or precision of the measurements. Let's discuss their implications:

1. Percent Error:

Percent error is calculated by comparing the absolute difference between the measured value and the expected value to the expected value itself. It is used to assess the accuracy of a measurement by quantifying how far off the measured value is from the expected value.

Percent error = (|Measured value - Expected value| / Expected value) * 100

A low percent error indicates a close agreement between the measured and expected values, suggesting higher accuracy. However, it does not provide information about the precision of the measurements or the consistency of the repeated measurements.

2. Percent Difference:

Percent difference compares the absolute difference between two measured values to their average. It is used to compare two experimental measurements or values obtained from different methods or sources.

Percent difference = (|Value 1 - Value 2| / (Value 1 + Value 2) / 2) * 100

Percent difference provides information about the relative difference between two measurements or values. It can indicate discrepancies or variations between the two measurements, but it does not directly address the accuracy or precision of individual measurements.

Accuracy and precision are distinct concepts:

- Accuracy refers to how close a measured value is to the true or expected value. A low percent error indicates higher accuracy.

- Precision refers to the consistency and reproducibility of measurements. It is related to the range of values obtained in repeated measurements and is typically assessed using measures such as standard deviation or uncertainty.

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Expressing the width of the box with two significant figures, the width is approximately 8.3 × 10⁻²⁹ m.

To determine the width of the box for the ground-level energy to be 5.0 MeV (mega-electron volts), we can use the equation for the energy levels of a particle in a box.

The energy levels of a particle in a one-dimensional box are given by the equation:

E = (n² × h²) / (8 × m × L²)

where:

E is the energy level of the particle,

n is the quantum number (1, 2, 3, ...),

h is the Planck's constant (approximately 6.626 × 10^-34 J·s),

m is the mass of the particle,

L is the width of the box.

We are given that the ground-level energy is 5.0 MeV. To convert this to joules, we'll use the conversion factor: 1 MeV = 1.602 × 10⁻¹³ J.

Converting the energy to joules:

E = 5.0 MeV × (1.602 × 10⁻¹³ J/MeV)

E = 8.01 × 10⁻¹³ J

For the ground-level energy (n = 1), the equation becomes:

8.01 × 10⁻¹³ J = (1² × h²) / (8 × m × L²)

Rearranging the equation to solve for the width of the box (L):

L² = (h²) / (8 × m × E)

Taking the square root of both sides:

L = √[(h²) / (8 × m × E)]

Substituting the known values:

L = √[(6.626 × 10⁻³⁴ J·s)² / (8 × m × 8.01 × 10⁻¹³ J)]

L = √[(4.3822769 × 10⁺⁶⁷ J²·s²) / (6.408 × 10⁻¹² kg)]

L = √[6.83428 × 10⁻⁻⁵⁶ J²·s²/kg]

L ≈ 8.273 × 10⁻²⁹ m

Expressing the width of the box with two significant figures, the width is approximately 8.3 × 10⁻²⁹ m.

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If the stationary mass is also 5 kg, then the bowling travel upto 2.5 m. If it is 10 kg the height it travel after the collision will be 1.25 m and if the stationary mass is 500 then the height will be 0.025 m.

An elastic collision is the short term force acting between two objects make them move apart or to one direction where, the total kinetic energy and momentum of the objects are conserved.

Here, the kinetic energy of the moving ball is equal to the work done by its weight and displacement.

hence Ke = f.ds

f = mg. ds  = 5 kg × 9.8 m/s² × 2.5 m = 122.5 J

Then this work done is equal to the potential energy of the stationary mass and:

122.5 J = mgh.

then for a mass of 5 kg , h = 122.5 /  (5 × 9.8 ) = 2.5 m

If the mass is 10 kg, h =   122.5 /  (10× 9.8 ) = 1.25 m

If the mass is 500 kg, h =  122.5 /  (500 × 9.8 ) = 0.025 m.

Therefore the height that the bowling travel back after collision varies with the mass of the stationary object.

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